
How do you simplify \[\dfrac{{\cos x}}{{\sin x}}\]?
Answer
570.6k+ views
Hint: Trigonometric functions are defined as real functions which relate any angle of a right angled triangle to the ratio of any two of its sides. We may use geometric definitions to evaluate trigonometric values. Here, it’s important that we know the cosine of theta is the ratio of the adjacent side (base) to the hypotenuse and the sine of theta is the ratio of the opposite side to the hypotenuse.
Complete step-by-step answer:
According to the given data, we need to simplify \[\dfrac{{\cos x}}{{\sin x}}\]
If in a right angled triangle \[\theta \] represents one of its acute angle then by definition we can write
\[\cos \theta = \dfrac{{Base}}{{Hypotenuse}}\] and,
\[\sin \theta = \dfrac{{Opposite}}{{Hypotenuse}}\]
Here we need to evaluate,
\[\dfrac{{\cos \theta }}{{\sin \theta }} = \cos \theta \times \dfrac{1}{{\sin \theta }} = \dfrac{{Base}}{{Hypotenuse}} \times \dfrac{{Hypotenuse}}{{Opposite}}\]
Hence, we finally get,
\[\dfrac{{\cos \theta }}{{\sin \theta }} = \dfrac{{Base}}{{Opposite}}\]
Also, we know that the cotangent of theta is the ratio of the adjacent side (base) to the opposite side.
According to the given data, \[\theta = x\].
Hence, when we substitute the value in the expression, we get
\[ \Rightarrow \dfrac{{\cos x}}{{\sin x}} = \dfrac{{Base}}{{Opposite}} = \cot x\]
Hence, the value of \[\dfrac{{\cos x}}{{\sin x}}\] is equivalent to \[\cot x\].
Note: Trigonometric functions are real functions which relate any angle of a right angled triangle to the ratio of any two of its sides. One should be careful while evaluating trigonometric values and rearranging the terms to convert from one function to the other. The widely used ones are sin, cos and tan. While the rest can be referred to as the inverse of the other trigonometric ratios, i.e., cosec, sec and cot respectively. If in a right angled triangle θ represents one of its acute angles then, \[\cot x = \dfrac{{\cos x}}{{\sin x}}\].
Complete step-by-step answer:
According to the given data, we need to simplify \[\dfrac{{\cos x}}{{\sin x}}\]
If in a right angled triangle \[\theta \] represents one of its acute angle then by definition we can write
\[\cos \theta = \dfrac{{Base}}{{Hypotenuse}}\] and,
\[\sin \theta = \dfrac{{Opposite}}{{Hypotenuse}}\]
Here we need to evaluate,
\[\dfrac{{\cos \theta }}{{\sin \theta }} = \cos \theta \times \dfrac{1}{{\sin \theta }} = \dfrac{{Base}}{{Hypotenuse}} \times \dfrac{{Hypotenuse}}{{Opposite}}\]
Hence, we finally get,
\[\dfrac{{\cos \theta }}{{\sin \theta }} = \dfrac{{Base}}{{Opposite}}\]
Also, we know that the cotangent of theta is the ratio of the adjacent side (base) to the opposite side.
According to the given data, \[\theta = x\].
Hence, when we substitute the value in the expression, we get
\[ \Rightarrow \dfrac{{\cos x}}{{\sin x}} = \dfrac{{Base}}{{Opposite}} = \cot x\]
Hence, the value of \[\dfrac{{\cos x}}{{\sin x}}\] is equivalent to \[\cot x\].
Note: Trigonometric functions are real functions which relate any angle of a right angled triangle to the ratio of any two of its sides. One should be careful while evaluating trigonometric values and rearranging the terms to convert from one function to the other. The widely used ones are sin, cos and tan. While the rest can be referred to as the inverse of the other trigonometric ratios, i.e., cosec, sec and cot respectively. If in a right angled triangle θ represents one of its acute angles then, \[\cot x = \dfrac{{\cos x}}{{\sin x}}\].
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

