How do you simplify $ \dfrac{11}{12}-\dfrac{2}{3} $ ?
Answer
599.7k+ views
Hint: From the question it had been asked to simplify $ \dfrac{11}{12}-\dfrac{2}{3} $ . We can clearly observe that the given question is in fractional form. We can simplify it by the below-shown process. As the given question is in fractions, we have to follow some process to simplify it. To simplify the given question, first, we need to get both fractions over a common denominator, and then calculation to be done to get the simplification.
Complete step by step answer:
The expression we have from the question is $ \dfrac{11}{12}-\dfrac{2}{3} $
Now, as we have already discussed above, first we need to get both fractions over a common denominator to get the question more simplified.
To get the common denominator, we have to do the LCM of the two denominators in the given question.
We know that LCM of $ 12 $ and $ 3 $ is $ 12 $
So, in this case, a common denominator is $ 12 $ , therefore we only need to adjust the fraction on the right.
So, now the process is to adjust the fraction on the right,
$ \dfrac{11}{12}-\dfrac{2}{3} $
$ \Rightarrow \dfrac{11}{12}-\left( \dfrac{4}{4}\times \dfrac{2}{3} \right) $
$ \Rightarrow \dfrac{11}{12}-\dfrac{8}{12} $
On furthermore simplification of the above expression, we get
$ \dfrac{11}{12}-\dfrac{8}{12}=\dfrac{3}{12} $
$ \Rightarrow \dfrac{1}{4} $
Therefore, $ \dfrac{11}{12}-\dfrac{2}{3}=\dfrac{1}{4} $
Hence, the given question is simplified.
Note:
We should be well aware of the fractions and their properties. We should be well known for the simplification of the fractions. We should be very careful while doing the calculation of fractions, as the calculation of fractions is somewhat difficult to do. We should be well known for the simplification of fractions. We should be very careful while simplifying these types of problems. Similarly we can solve $ \dfrac{10}{15}-\dfrac{2}{3}=\dfrac{10}{15}-\dfrac{10}{15}=0 $ .
Complete step by step answer:
The expression we have from the question is $ \dfrac{11}{12}-\dfrac{2}{3} $
Now, as we have already discussed above, first we need to get both fractions over a common denominator to get the question more simplified.
To get the common denominator, we have to do the LCM of the two denominators in the given question.
We know that LCM of $ 12 $ and $ 3 $ is $ 12 $
So, in this case, a common denominator is $ 12 $ , therefore we only need to adjust the fraction on the right.
So, now the process is to adjust the fraction on the right,
$ \dfrac{11}{12}-\dfrac{2}{3} $
$ \Rightarrow \dfrac{11}{12}-\left( \dfrac{4}{4}\times \dfrac{2}{3} \right) $
$ \Rightarrow \dfrac{11}{12}-\dfrac{8}{12} $
On furthermore simplification of the above expression, we get
$ \dfrac{11}{12}-\dfrac{8}{12}=\dfrac{3}{12} $
$ \Rightarrow \dfrac{1}{4} $
Therefore, $ \dfrac{11}{12}-\dfrac{2}{3}=\dfrac{1}{4} $
Hence, the given question is simplified.
Note:
We should be well aware of the fractions and their properties. We should be well known for the simplification of the fractions. We should be very careful while doing the calculation of fractions, as the calculation of fractions is somewhat difficult to do. We should be well known for the simplification of fractions. We should be very careful while simplifying these types of problems. Similarly we can solve $ \dfrac{10}{15}-\dfrac{2}{3}=\dfrac{10}{15}-\dfrac{10}{15}=0 $ .
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