Answer
385.2k+ views
Hint: For answering this question we need to draw the graph of $y=-\dfrac{3}{5}x+1$ . For drawing the graph of the straight line we will find the intercepts of the given equation of the straight line and plot them and join them and extend the line formed. The intercepts are the respective points when the other variable is zero.
Complete step-by-step solution:
Now considering from the question we have to draw the graph of $y=-\dfrac{3}{5}x+1$ .
From the basics of the concept we know that for drawing the graph of the straight line we need to find the intercepts of the given equation of the straight line and plot them and join them and extend the line formed.
The intercepts are the respective points when the other variable is zero.
The $\text{x-intercept}$ is given by substituting $y=0$ in the given equation of the straight line.
After substituting we will have
$\begin{align}
& \Rightarrow 0=-\dfrac{3}{5}x+1 \\
& \Rightarrow -1=-\dfrac{3}{5}x \\
& \Rightarrow x=\dfrac{5}{3} \\
\end{align}$
The $\text{y-intercept}$ is given by substituting $x=0$ in the given equation of the straight line.
After substituting we will have
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 0 \right)+1 \\
& \Rightarrow y=1 \\
\end{align}$
So now we have two points lying on the straight line $\left( 0,1 \right)$ and $\left( \dfrac{5}{3},0 \right)$ .
Now we will plot these two points and join them and extend them to form a straight line. The graph of the straight line is shown below.
Note: For answering this question we need to draw the graph of the given equation of the straight line so we need to be careful while plotting the points and extending the line. We should be careful while performing the calculations. The slope of this given straight line \[y=-\dfrac{3}{5}x+1\] is $\dfrac{-3}{5}$ as we know that the slope intercept form is given as $y=mx+c$ where $m$ is the slope.
Complete step-by-step solution:
Now considering from the question we have to draw the graph of $y=-\dfrac{3}{5}x+1$ .
From the basics of the concept we know that for drawing the graph of the straight line we need to find the intercepts of the given equation of the straight line and plot them and join them and extend the line formed.
The intercepts are the respective points when the other variable is zero.
The $\text{x-intercept}$ is given by substituting $y=0$ in the given equation of the straight line.
After substituting we will have
$\begin{align}
& \Rightarrow 0=-\dfrac{3}{5}x+1 \\
& \Rightarrow -1=-\dfrac{3}{5}x \\
& \Rightarrow x=\dfrac{5}{3} \\
\end{align}$
The $\text{y-intercept}$ is given by substituting $x=0$ in the given equation of the straight line.
After substituting we will have
$\begin{align}
& \Rightarrow y=-\dfrac{3}{5}\left( 0 \right)+1 \\
& \Rightarrow y=1 \\
\end{align}$
So now we have two points lying on the straight line $\left( 0,1 \right)$ and $\left( \dfrac{5}{3},0 \right)$ .
Now we will plot these two points and join them and extend them to form a straight line. The graph of the straight line is shown below.
![seo images](https://www.vedantu.com/question-sets/88e98d4e-7d06-4165-892d-87d5160f52234354702166130252546.png)
Note: For answering this question we need to draw the graph of the given equation of the straight line so we need to be careful while plotting the points and extending the line. We should be careful while performing the calculations. The slope of this given straight line \[y=-\dfrac{3}{5}x+1\] is $\dfrac{-3}{5}$ as we know that the slope intercept form is given as $y=mx+c$ where $m$ is the slope.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)