
How do you graph $x-1=y?$
Answer
446.4k+ views
Hint: To draw a line you need two of its points, which you can connect. To find two points, you can plug any value for one variable, and solve for the other. For example: let’s choose $x=0$
The equation becomes $0-1=y$ and so $y=-1$
If your line goes through two distinct points of the equation, then your line is correct.
Complete step by step solution:
As we know that given equation is:
$x-1=y...(i)$
This is a line, since write equation as in the form of $y-x+1=0$
Which follows the pattern of the general line $ax+by+c=0$
To draw a line you need two of its points. Which you can connect.
To find two points, you can plug any value for one variable and solve for the other.
Put $x=0$ the equation become $0-1=y$
And so $y=-1$
Therefore, the point will be $\left( 0,-1 \right)$
$x=0$ and $y=-1$
Put $x=1$ in the equation no. $(i)$
$1-1=y$
And so $y=0$
Therefore the second point will be $\left( 1,0 \right)$
First point to plot the graph is $\left( 0,-1 \right)$and second point to plot the point graph is $\left( 1,0 \right)$ then connect these two points and make the line.
Hence, in this way you can graph $x-1=y$
Additional Information:
Graph a line using slope intercept form is:
The equation of a line in explicit from is:
$y=mx+q,$ where $'m'$ is the slope and $'q'$ is the $y$-intercept.
It is easier to show the procedure with some examples.
$y=2,$ this is line parallel to $x$-axis and it passes from the point $P\left( 0,2 \right)$
$y=x+1,$ this line is parallel to bisector of the $I$ and $II$ quadrants and it passes from the point $P\left( 0,1 \right)$
Graph $\left\{ x+1\left[ -10,10,-5,5 \right] \right\}$
$y=-\dfrac{1}{2}x-1$ we have to find the point $P\left( 0,-1 \right)$ From this point we have to ‘count’ $2$ units. To the left and then $2$ units to the up. So we can find the point $Q\left( -2,0 \right)$ then we have to join the two points found.
Note:
Write the given equation in the general pattern as $ax+by+c=0$ Remember that here you have to draw a line on a graph so you will require two points for draw a line. So, as require two points you have to assume $x=0$ and $x=1$
Do not forget to connect this point as you have to draw a line.
The equation becomes $0-1=y$ and so $y=-1$
If your line goes through two distinct points of the equation, then your line is correct.
Complete step by step solution:
As we know that given equation is:
$x-1=y...(i)$
This is a line, since write equation as in the form of $y-x+1=0$
Which follows the pattern of the general line $ax+by+c=0$
To draw a line you need two of its points. Which you can connect.
To find two points, you can plug any value for one variable and solve for the other.
Put $x=0$ the equation become $0-1=y$
And so $y=-1$
Therefore, the point will be $\left( 0,-1 \right)$
$x=0$ and $y=-1$
Put $x=1$ in the equation no. $(i)$
$1-1=y$
And so $y=0$
Therefore the second point will be $\left( 1,0 \right)$
First point to plot the graph is $\left( 0,-1 \right)$and second point to plot the point graph is $\left( 1,0 \right)$ then connect these two points and make the line.
Hence, in this way you can graph $x-1=y$
Additional Information:
Graph a line using slope intercept form is:
The equation of a line in explicit from is:
$y=mx+q,$ where $'m'$ is the slope and $'q'$ is the $y$-intercept.
It is easier to show the procedure with some examples.
$y=2,$ this is line parallel to $x$-axis and it passes from the point $P\left( 0,2 \right)$
$y=x+1,$ this line is parallel to bisector of the $I$ and $II$ quadrants and it passes from the point $P\left( 0,1 \right)$
Graph $\left\{ x+1\left[ -10,10,-5,5 \right] \right\}$
$y=-\dfrac{1}{2}x-1$ we have to find the point $P\left( 0,-1 \right)$ From this point we have to ‘count’ $2$ units. To the left and then $2$ units to the up. So we can find the point $Q\left( -2,0 \right)$ then we have to join the two points found.
Note:
Write the given equation in the general pattern as $ax+by+c=0$ Remember that here you have to draw a line on a graph so you will require two points for draw a line. So, as require two points you have to assume $x=0$ and $x=1$
Do not forget to connect this point as you have to draw a line.
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