
How do you graph \[x - y = 10\]\[?\]
Answer
550.8k+ views
Hint: The given question describes the arithmetic operation of addition/ subtraction/ multiplication/ division. We need to know how to find the value of \[y\] from the above equation. Also, this problem involves substituting \[x\] values in the given equation to find the value \[y\]. By using \[x\] and \[y\] values we would draw the graph.
Complete step by step solution:
The given equation is shown below,
\[x - y = 10\]
The above equation can also be written as,
\[y = x - 10 \to \left( 1 \right)\]
We would draw the graph for the above equation. As a first step, we would assume \[x\] values as given below,
\[x = ..... - 2, - 1,0,1,2,.....\]
By substituting the \[x\] values in the equation \[\left( 1 \right)\], we can find the \[y\] values.
Let’s substitute \[x = - 2\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = - 2 - 10 \\
y = - 12 \\
\]
When \[x = - 2\] the value of \[y\] is \[ - 12\]
Let’s substitute \[x = - 1\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = - 1 - 10 \\
y = - 11 \\
\]
When \[x = - 1\] the value of \[y\] is \[ - 11\]
Let’s substitute \[x = 0\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 0 - 10 \\
y = - 10 \\
\]
When \[x = 0\] the value of \[y\] is \[ - 10\]
Let’s substitute \[x = 1\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 1 - 10 \\
y = - 9 \\
\]
When \[x = 1\] the value of \[y\] is \[ - 9\]
Let’s substitute \[x = 2\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 2 - 10 \\
y = - 8 \\
\]
When \[x = 2\] then the value of \[y\] is \[ - 8\]
Let’s make a tabular column by using the \[x\] and \[y\] values.
By using these points we can easily draw the graph,
The above graph represents the equation \[y = x - 10\]
Note: \[y\] is the function of \[x\] so it can also be written as \[f\left( x \right)\]. Also, this type of question involves the arithmetic operations like addition/ subtraction/ multiplication/ division. For finding the value of \[y\] point we can assume the \[x\] values. Note that if an equation is in the form of \[y = mx + c\], the graph always will be a straight line.
Complete step by step solution:
The given equation is shown below,
\[x - y = 10\]
The above equation can also be written as,
\[y = x - 10 \to \left( 1 \right)\]
We would draw the graph for the above equation. As a first step, we would assume \[x\] values as given below,
\[x = ..... - 2, - 1,0,1,2,.....\]
By substituting the \[x\] values in the equation \[\left( 1 \right)\], we can find the \[y\] values.
Let’s substitute \[x = - 2\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = - 2 - 10 \\
y = - 12 \\
\]
When \[x = - 2\] the value of \[y\] is \[ - 12\]
Let’s substitute \[x = - 1\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = - 1 - 10 \\
y = - 11 \\
\]
When \[x = - 1\] the value of \[y\] is \[ - 11\]
Let’s substitute \[x = 0\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 0 - 10 \\
y = - 10 \\
\]
When \[x = 0\] the value of \[y\] is \[ - 10\]
Let’s substitute \[x = 1\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 1 - 10 \\
y = - 9 \\
\]
When \[x = 1\] the value of \[y\] is \[ - 9\]
Let’s substitute \[x = 2\] in the equation \[\left( 1 \right)\], we get
\[\left( 1 \right) \to y = x - 10\]
\[
y = 2 - 10 \\
y = - 8 \\
\]
When \[x = 2\] then the value of \[y\] is \[ - 8\]
Let’s make a tabular column by using the \[x\] and \[y\] values.
| \[x\] | \[ - 2\] | \[ - 1\] | \[0\] | \[1\] | \[2\] |
| \[y\] | \[ - 12\] | \[ - 11\] | \[ - 10\] | \[ - 9\] | \[ - 8\] |
By using these points we can easily draw the graph,
The above graph represents the equation \[y = x - 10\]
Note: \[y\] is the function of \[x\] so it can also be written as \[f\left( x \right)\]. Also, this type of question involves the arithmetic operations like addition/ subtraction/ multiplication/ division. For finding the value of \[y\] point we can assume the \[x\] values. Note that if an equation is in the form of \[y = mx + c\], the graph always will be a straight line.
Recently Updated Pages
Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

The coating formed on the metals such as iron silver class 12 chemistry CBSE

Metals are refined by using different methods Which class 12 chemistry CBSE

What do you understand by denaturation of proteins class 12 chemistry CBSE

Assertion Nitrobenzene is used as a solvent in FriedelCrafts class 12 chemistry CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

