
How do you find the product ${(x + 3)^2}$?
Answer
546.6k+ views
Hint: The Square of a number or expression is the result that we get when the number or expression is multiplied by itself. For multiplying two expressions or an expression by itself we use the distributive property of multiplication, i.e. multiplying each term of an expression by each term of the other expression.
Complete step-by-step solution:
We have to find the product ${(x + 3)^2}$.
We can see that we have to find the square of the expression $(x + 3)$. In other words, we have to find the product of $(x + 3)$ multiplied by itself, i.e. we have to find,
$(x + 3) \times (x + 3)$
For this we will use the distributive property of multiplication wherein we multiply each term of an expression by each term of the other expression. This is given by,
$
\Rightarrow (ax + b) \times (cx + d) \\
\Rightarrow (ax \times (cx + d)) + (b \times (cx + d)) \\
\Rightarrow (ax \times cx) + (ax \times d) + (b \times cx) + (b \times d) \\
$
Thus, we can find the product of $(x + 3) \times (x + 3)$ as,
$
\Rightarrow (x + 3) \times (x + 3) \\
\Rightarrow (x \times (x + 3)) + (3 \times (x + 3)) \\
\Rightarrow (x \times x) + (x \times 3) + (3 \times x) + (3 \times 3) \\
\Rightarrow {x^2} + 3x + 3x + 9 \\
\Rightarrow {x^2} + 6x + 9 \\
$
We get the resulting product as $({x^2} + 6x + 9)$
Alternatively, we can also find the product of expression having two terms using the formula,
${(a + b)^2} = {a^2} + 2ab + {b^2}$
Putting $a = x$ and $b = 3$ we get,
$
\Rightarrow {(x + 3)^2} \\
\Rightarrow {x^2} + 2 \times x \times 3 + {3^2} \\
\Rightarrow {x^2} + 6x + 9 \\
$
Hence, the product of ${(x + 3)^2}$ is $({x^2} + 6x + 9)$
Note: To find the square of an expression we multiply the expression by itself. For multiplication we can use the distributive property of multiplication wherein we multiply each term of an expression by each term of the other expression. For finding the square of an expression with two terms we can also use the direct formula given by, ${(a + b)^2} = {a^2} + 2ab + {b^2}$. The degree of the resulting expression that we get by squaring an expression is twice the degree of the given expression.
Complete step-by-step solution:
We have to find the product ${(x + 3)^2}$.
We can see that we have to find the square of the expression $(x + 3)$. In other words, we have to find the product of $(x + 3)$ multiplied by itself, i.e. we have to find,
$(x + 3) \times (x + 3)$
For this we will use the distributive property of multiplication wherein we multiply each term of an expression by each term of the other expression. This is given by,
$
\Rightarrow (ax + b) \times (cx + d) \\
\Rightarrow (ax \times (cx + d)) + (b \times (cx + d)) \\
\Rightarrow (ax \times cx) + (ax \times d) + (b \times cx) + (b \times d) \\
$
Thus, we can find the product of $(x + 3) \times (x + 3)$ as,
$
\Rightarrow (x + 3) \times (x + 3) \\
\Rightarrow (x \times (x + 3)) + (3 \times (x + 3)) \\
\Rightarrow (x \times x) + (x \times 3) + (3 \times x) + (3 \times 3) \\
\Rightarrow {x^2} + 3x + 3x + 9 \\
\Rightarrow {x^2} + 6x + 9 \\
$
We get the resulting product as $({x^2} + 6x + 9)$
Alternatively, we can also find the product of expression having two terms using the formula,
${(a + b)^2} = {a^2} + 2ab + {b^2}$
Putting $a = x$ and $b = 3$ we get,
$
\Rightarrow {(x + 3)^2} \\
\Rightarrow {x^2} + 2 \times x \times 3 + {3^2} \\
\Rightarrow {x^2} + 6x + 9 \\
$
Hence, the product of ${(x + 3)^2}$ is $({x^2} + 6x + 9)$
Note: To find the square of an expression we multiply the expression by itself. For multiplication we can use the distributive property of multiplication wherein we multiply each term of an expression by each term of the other expression. For finding the square of an expression with two terms we can also use the direct formula given by, ${(a + b)^2} = {a^2} + 2ab + {b^2}$. The degree of the resulting expression that we get by squaring an expression is twice the degree of the given expression.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

