
How do you evaluate $\cos W=0.6157$?
Answer
550.2k+ views
Hint: Now we are given with $\cos W=1.6157$ . We will make use of the inverse function of cos to write another equation in ${{\cos }^{-1}}$ . Now we will find the value of cos inverse and hence find the value of W.
Complete step by step answer:
Now let us first understand the trigonometric functions and inverse trigonometric functions.
Trigonometric function are nothing but ratios of a right angle triangle,
Now the given function cos is ratio of adjacent side and hypotenuse in a right angle triangle.
Hence $\cos \theta $ gives us the value of the ratio for each angle $\theta $ .
Now for each trigonometric ratio we have its inverse trigonometric function.
Inverse function of any function is nothing but a function which nullifies the effect of the function. Let us understand this by an example.
If f is a function such that $f\left( x \right)=y$ then the function g is called the inverse function of f if $g\left( y \right)=x$ for all values of x and y.
Now the inverse function of cos is denoted by ${{\cos }^{-1}}x$ or arc cos .
Hence we can say that if $\cos \theta =x$ then ${{\cos }^{-1}}x=\theta $ .
Now we are given with an equation $\cos W=0.6157$ .
Hence we can say that ${{\cos }^{-1}}0.6517=W$ .
Now we calculating the value of ${{\cos }^{-1}}0.6517$ we get, ${{\cos }^{-1}}0.6157={{52}^{\circ }}$ .
Hence the value of W is ${{52}^{\circ }}$ .
Note:
Now note that the inverse function of f is generally denoted by ${{f}^{-1}}$ . The negative power is just a notation and should not be considered as a fraction. Hence we can say ${{f}^{-1}}\left( x \right)\ne \frac{1}{f\left( x \right)}$ . Also it should be noted that inverse function of all functions need not exist. The functions will have an inverse function only if the function is bijective.
Complete step by step answer:
Now let us first understand the trigonometric functions and inverse trigonometric functions.
Trigonometric function are nothing but ratios of a right angle triangle,
Now the given function cos is ratio of adjacent side and hypotenuse in a right angle triangle.
Hence $\cos \theta $ gives us the value of the ratio for each angle $\theta $ .
Now for each trigonometric ratio we have its inverse trigonometric function.
Inverse function of any function is nothing but a function which nullifies the effect of the function. Let us understand this by an example.
If f is a function such that $f\left( x \right)=y$ then the function g is called the inverse function of f if $g\left( y \right)=x$ for all values of x and y.
Now the inverse function of cos is denoted by ${{\cos }^{-1}}x$ or arc cos .
Hence we can say that if $\cos \theta =x$ then ${{\cos }^{-1}}x=\theta $ .
Now we are given with an equation $\cos W=0.6157$ .
Hence we can say that ${{\cos }^{-1}}0.6517=W$ .
Now we calculating the value of ${{\cos }^{-1}}0.6517$ we get, ${{\cos }^{-1}}0.6157={{52}^{\circ }}$ .
Hence the value of W is ${{52}^{\circ }}$ .
Note:
Now note that the inverse function of f is generally denoted by ${{f}^{-1}}$ . The negative power is just a notation and should not be considered as a fraction. Hence we can say ${{f}^{-1}}\left( x \right)\ne \frac{1}{f\left( x \right)}$ . Also it should be noted that inverse function of all functions need not exist. The functions will have an inverse function only if the function is bijective.
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