How can I calculate the pH of $NaOH$?
Answer
598.5k+ views
Hint: $NaOH$ is an inorganic compound known by the name sodium hydroxide and caustic soda. It is a white solid ionic compound which consists of sodium cations represented by $N{{a}^{+}}$ and anions represented by hydroxide ion $O{{H}^{-}}$.
Complete answer:
pH represents potential of hydrogen or power of hydrogen. It is a scale which is used to detect whether the given solution is acidic or basic in nature. Generally scale ranges from 0-14 where the solutions having pH less than 7 acidic in nature, greater than 7 basic in nature while at exact 7 the given solution is said to be neutral.
To know about the pH value of $NaOH$ we firstly know about the molarity of the solution where molarity can be defined as the concentration of a solution which is expressed as a number of moles of solute per liter of the solution. Let us suppose molarity of the solution is 0.1M. Now we know that $NaOH$ is a strong base then it will produce $0.1mol/L$ of $OH$ ions in the solution. pH can be calculated with the negative log of $OH$ ions produced so we can say that $pOH$ will be equal to 1.
We know that $pH+pOH=14$, $\therefore pH=13$
Hence we can say that pH of $NaOH$/is 13.
Note:
The pH scale is logarithmic and it inversely indicates the concentration of the hydrogen ions in the solution. The formula used to calculate the pH value basically equals the negative of the base 10 logarithmic of the molar concentration of hydrogen ions in the solution.
Complete answer:
pH represents potential of hydrogen or power of hydrogen. It is a scale which is used to detect whether the given solution is acidic or basic in nature. Generally scale ranges from 0-14 where the solutions having pH less than 7 acidic in nature, greater than 7 basic in nature while at exact 7 the given solution is said to be neutral.
To know about the pH value of $NaOH$ we firstly know about the molarity of the solution where molarity can be defined as the concentration of a solution which is expressed as a number of moles of solute per liter of the solution. Let us suppose molarity of the solution is 0.1M. Now we know that $NaOH$ is a strong base then it will produce $0.1mol/L$ of $OH$ ions in the solution. pH can be calculated with the negative log of $OH$ ions produced so we can say that $pOH$ will be equal to 1.
We know that $pH+pOH=14$, $\therefore pH=13$
Hence we can say that pH of $NaOH$/is 13.
Note:
The pH scale is logarithmic and it inversely indicates the concentration of the hydrogen ions in the solution. The formula used to calculate the pH value basically equals the negative of the base 10 logarithmic of the molar concentration of hydrogen ions in the solution.
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