Question

What is the highest degree of the quadratic equation in x?
Equation $ = 2{x^2} + \dfrac{5}{2}x - \sqrt 3 = 0$

Answer 1

Hint: In this problem they have asked to calculate the highest degree of a linear equation. For this, first we will define what a quadratic equation is and then we can write the degree of the quadratic equation. By observing the degrees of quadratic equation we can find the Highest Degree of quadratic Equation.

Complete step-by-step solution:
Quadratic equations are the polynomial equations of degree 2 in one variable of type $f\left( x \right) = a{x^2} + bx + c$ where a, b, c, are real numbers and a is not equal to zero. It is the general form of a quadratic equation where ‘a’ is called the leading coefficient and ‘c’ is called the absolute term of $f\left( x \right)$. The values of x satisfying the quadratic equation are the roots of the quadratic equation.
Now, we will observe the degree of the equation $2{x^2} + \dfrac{5}{2}x - \sqrt 3 = 0$ .
We can observe the degree of quadratic equations as 2 and 1. Since, the exponents of the variables is always 2 and 1.
So, the highest degree of the equation is 2.

Note: In this problem, we have only asked about the degree of the quadratic equation, so we have defined that and observed about the degrees of this equation. A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. Sometimes, questions may come from linear or cubic equations. At that time also we have to follow the same procedure.