
What happens when sodium chloride is added to a solution containing lead (II) nitrate?
Answer
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Hint :A chemical reaction occurs when one or more substances, known as reactants, are converted into one or more different substances, known as products. Chemical elements or compounds are examples of substances.
Complete Step By Step Answer:
When a sodium chloride is added to a solution containing lead (II) nitrate, a white precipitate of (fairly) insoluble lead chloride will result.
\[NaCl + Pb{\left( {N{O_3}} \right)_2} \to NaN{O_3}{\text{ }} + {\text{ }}PbC{l_2}\]
\[P{b^{2 + }}\, + \,2C{l^ - } \to PbC{l_2}(s) \downarrow \]
When a sodium chloride solution is added to a lead nitrate solution, a precipitate of lead chloride and sodium nitrate is formed. Coldwater makes the precipitate lead chloride insoluble, but hot water makes it soluble. Due to the fact that sodium is more reactive than lead, it can displace it from its compound. Both compounds' positive components would be swapped. Sodium nitrate and a white precipitate of lead (II) chloride are formed in a double decomposition reaction. There are no reactive ions in their solid-state; the lead (II) and nitrate form ionic bonds with each other. Nitrate has a charge of\[ - 1\], while lead has a charge of\[ + 2\]. The sodium and chlorine atoms are similarly inactive because they are bound together by their charge, which is \[ + 1\] for sodium and \[ - 1\] for chlorine. Opposites are drawn together. Positive energy attracts harmful energy.
Note :
The ions are free, dissolved in the solution, and ready to react if both substances are aqueous (dissolved in water). As a result, the positively charged Lead (II) ions combine with the negatively charged chloride ions to create a dense precipitate that settles to the bottom of the bottle.
Complete Step By Step Answer:
When a sodium chloride is added to a solution containing lead (II) nitrate, a white precipitate of (fairly) insoluble lead chloride will result.
\[NaCl + Pb{\left( {N{O_3}} \right)_2} \to NaN{O_3}{\text{ }} + {\text{ }}PbC{l_2}\]
\[P{b^{2 + }}\, + \,2C{l^ - } \to PbC{l_2}(s) \downarrow \]
When a sodium chloride solution is added to a lead nitrate solution, a precipitate of lead chloride and sodium nitrate is formed. Coldwater makes the precipitate lead chloride insoluble, but hot water makes it soluble. Due to the fact that sodium is more reactive than lead, it can displace it from its compound. Both compounds' positive components would be swapped. Sodium nitrate and a white precipitate of lead (II) chloride are formed in a double decomposition reaction. There are no reactive ions in their solid-state; the lead (II) and nitrate form ionic bonds with each other. Nitrate has a charge of\[ - 1\], while lead has a charge of\[ + 2\]. The sodium and chlorine atoms are similarly inactive because they are bound together by their charge, which is \[ + 1\] for sodium and \[ - 1\] for chlorine. Opposites are drawn together. Positive energy attracts harmful energy.
Note :
The ions are free, dissolved in the solution, and ready to react if both substances are aqueous (dissolved in water). As a result, the positively charged Lead (II) ions combine with the negatively charged chloride ions to create a dense precipitate that settles to the bottom of the bottle.
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