Question

How many grams are in 5.66 mol of $CaC{{O}_{3}}$?

Answer 1

Hint: The answer here is dependent on the calculation of the number of moles of the given compound by taking the value of the molar mass of calcium carbonate and the multiplication of the values gives the answer.

Complete step by step answer:
The concept of the basic chemistry which deals with the calculation of some entities such as mole of the substance, conversion of moles into molecules, conversion of grams into moles and many other related calculations are known to us.
Let us see the conversion of the above given data from grams to number of moles.
- Calcium carbonate is formed by the combination of a divalent cation of calcium with the divalent anion that is the carbonate ion.
- Calcium carbonate with the molecular formula $CaC{{O}_{3}}$ has molecular mass say ‘x’ g/mol.
- To find the molar mass of this compound let us multiply each atom with its molar mass and the respective number of atoms and sum of all the atoms will give the molar mass of the compound.
- Now, calcium is having the molar mass of 40 g/mol and it is single atom here whereas carbon has molar ,mass of 12 g/mol and is also single atom and the oxygen atom has the molar mass of 16 g/mol and therefore it is triatomic here.
Thus by the multiplication of molar masses of each atom with its respective number of atom we have,
\[40.08\times 1 + 12\times 1 + 16\times 3\approx 100.1 g/mol\]
Therefore, the molar mass of calcium carbonate is 100.1 g/mol
Thus, the mass of 5.66 mol of calcium carbonate will be,
\[5.66mol\times 100.1g/mol\approx 566.5g\]
Thus, the correct answer is there are about 566.5 grams of calcium carbonate in 5.66 mol of calcium carbonate.

Note: Number of moles and number of molecules are not to be confused because one mole of the substance is the quantity of that substance and one molecule is the number of moles of substance multiplied by the Avogadro number that is $6.022\times {{10}^{23}}$