
Give possible expressions for the length and breadth of the rectangle whose area is given by,
(i) $25{{a}^{2}}-35a+12$
(ii) \[24{{x}^{2}}-15x\]
Answer
625.5k+ views
Hint: Area of a rectangle is given by,
$Area=length\times breadth$
So, we have to find two expressions, which on multiplication produces the given expression of area. We need to find the factors of the given expression for the area.
Complete step-by-step answer:
In question, expression for area is given. We need to find the expressions which are possible for length and breadth.
So, we need to find two polynomials which when multiplied together produce the expression given for area.
It means we need to split the given area for expression into simpler polynomials.
i.e. we need to find the factors of the given expression for area.
Thus, we will factorize the given polynomial expression for area and get the expressions for length and breadth.
(i) Given expression for area $=25{{a}^{2}}-35a+12$.
As, $length\times breadth=area$ and area is quadratic.
So, the order of polynomials for length and breadth will be less than or equal to 2.
Factorization of $25{{a}^{2}}-35a+12$.
For factorising the above quadratic expression, we need to split the middle term.
$\begin{align}
& 25{{a}^{2}}-35a+12=25{{a}^{2}}-20a-15a+12 \\
& =5a\left( 5a-4 \right)-3\left( 5a-4 \right) \\
& =\left( 5a-3 \right)\left( 5a-4 \right) \\
& \Rightarrow 25{{a}^{2}}-35a+12=\left( 5a-3 \right)\left( 5a-4 \right) \\
\end{align}$
Thus, for area $=25{{a}^{2}}-35a+12$, we can have following pairs of forms of length and breadth,
Similarly, we can do for (ii) \[24{{x}^{2}}-15x\].
Let us first factorise \[24{{x}^{2}}-15x\].
Taking $3x$ common, we will get,
\[24{{x}^{2}}-15x=3x\left( 8x-5 \right)\]
Thus, for area \[=24{{x}^{2}}-15x\], we can have the following possible forms of length and breadth,
Note: A student can make mistakes by not considering the form when length = 1 and breadth is quadratic or length is quadratic and breadth is 1. But these forms will also be taken in answer as taking these forms will also lead to the required area.
$Area=length\times breadth$
So, we have to find two expressions, which on multiplication produces the given expression of area. We need to find the factors of the given expression for the area.
Complete step-by-step answer:
In question, expression for area is given. We need to find the expressions which are possible for length and breadth.
So, we need to find two polynomials which when multiplied together produce the expression given for area.
It means we need to split the given area for expression into simpler polynomials.
i.e. we need to find the factors of the given expression for area.
Thus, we will factorize the given polynomial expression for area and get the expressions for length and breadth.
(i) Given expression for area $=25{{a}^{2}}-35a+12$.
As, $length\times breadth=area$ and area is quadratic.
So, the order of polynomials for length and breadth will be less than or equal to 2.
Factorization of $25{{a}^{2}}-35a+12$.
For factorising the above quadratic expression, we need to split the middle term.
$\begin{align}
& 25{{a}^{2}}-35a+12=25{{a}^{2}}-20a-15a+12 \\
& =5a\left( 5a-4 \right)-3\left( 5a-4 \right) \\
& =\left( 5a-3 \right)\left( 5a-4 \right) \\
& \Rightarrow 25{{a}^{2}}-35a+12=\left( 5a-3 \right)\left( 5a-4 \right) \\
\end{align}$
Thus, for area $=25{{a}^{2}}-35a+12$, we can have following pairs of forms of length and breadth,
| Length | Breadth |
| 1 | $25{{a}^{2}}-35a+12$ |
| $25{{a}^{2}}-35a+12$ | 1 |
| $5a-3$ | $5a-4$ |
| $5a-4$ | $5a-3$ |
Similarly, we can do for (ii) \[24{{x}^{2}}-15x\].
Let us first factorise \[24{{x}^{2}}-15x\].
Taking $3x$ common, we will get,
\[24{{x}^{2}}-15x=3x\left( 8x-5 \right)\]
Thus, for area \[=24{{x}^{2}}-15x\], we can have the following possible forms of length and breadth,
| Length | Breadth |
| 1 | \[24{{x}^{2}}-15x\] |
| \[24{{x}^{2}}-15x\] | 1 |
| $3x$ | \[8x-5\] |
| \[8x-5\] | $3x$ |
Note: A student can make mistakes by not considering the form when length = 1 and breadth is quadratic or length is quadratic and breadth is 1. But these forms will also be taken in answer as taking these forms will also lead to the required area.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Trending doubts
Which country won the ICC Men's ODI World Cup in 2023?

In cricket, how many legal balls are there in a standard over?

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

What does "powerplay" mean in limited-overs cricket?

What is the "Powerplay" in T20 cricket?

