
What is the formula of the compound formed by Ba and F?
Answer
491.7k+ views
Hint : Chemical compounds like many laboratory acids are composed or constitute of the elements present in the periodic table. Various chemical elements combine in different ratios or proportions to form varieties of compounds like acids and bases and other important chemicals.
Complete Step By Step Answer:
So, let’s first know about the elements, of which symbols are given in the question.
So, ‘Ba’ is basically the element ‘Barium’.
And the symbol ‘F’ stands for the element Fluorine.
So, let’s know in detail about the compound they will form and what the conditions are:
So, as we know that Barium is the metal and it belongs to the ‘Group $ - 2 $ of the periodic table. And it forms an ion with the $ 2 $ positive charge i.e. $ + 2 $ : $ B{a^{2 + }} $
On the other hand, ‘Fluorine’ is the non-metal which is present in the ‘group $ - 17 $ ’ of the periodic table and it forms ion easily with the $ - 1 $ negative charge. So, it will be having an anion as $ {F^{ - 1}} $ .
So, to form a compound, both the elements must satisfy the charges of each other and balance the compound.
So as we know from above, Barium bears charge $ + 2 $ and fluorine has a charge of $ - 1 $ . So two atoms of Fluorine are required to satisfy the $ + 2 $ positive charge of Barium.
Hence the compound formed by Ba and F will be $ Ba{F_2} $ i.e. Barium Fluoride.
Note :
Since we know that the bonds formed by the combination of the metal and the non-metal are the ionic bonds. And ionic bonds or ionic compounds are neutral in nature, so they act and the anion needs to balance the charge of each other to form ionic compounds.
Complete Step By Step Answer:
So, let’s first know about the elements, of which symbols are given in the question.
So, ‘Ba’ is basically the element ‘Barium’.
And the symbol ‘F’ stands for the element Fluorine.
So, let’s know in detail about the compound they will form and what the conditions are:
So, as we know that Barium is the metal and it belongs to the ‘Group $ - 2 $ of the periodic table. And it forms an ion with the $ 2 $ positive charge i.e. $ + 2 $ : $ B{a^{2 + }} $
On the other hand, ‘Fluorine’ is the non-metal which is present in the ‘group $ - 17 $ ’ of the periodic table and it forms ion easily with the $ - 1 $ negative charge. So, it will be having an anion as $ {F^{ - 1}} $ .
So, to form a compound, both the elements must satisfy the charges of each other and balance the compound.
So as we know from above, Barium bears charge $ + 2 $ and fluorine has a charge of $ - 1 $ . So two atoms of Fluorine are required to satisfy the $ + 2 $ positive charge of Barium.
Hence the compound formed by Ba and F will be $ Ba{F_2} $ i.e. Barium Fluoride.
Note :
Since we know that the bonds formed by the combination of the metal and the non-metal are the ionic bonds. And ionic bonds or ionic compounds are neutral in nature, so they act and the anion needs to balance the charge of each other to form ionic compounds.
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