
What is the formula of the compound formed by Ba and F?
Answer
504k+ views
Hint : Chemical compounds like many laboratory acids are composed or constitute of the elements present in the periodic table. Various chemical elements combine in different ratios or proportions to form varieties of compounds like acids and bases and other important chemicals.
Complete Step By Step Answer:
So, let’s first know about the elements, of which symbols are given in the question.
So, ‘Ba’ is basically the element ‘Barium’.
And the symbol ‘F’ stands for the element Fluorine.
So, let’s know in detail about the compound they will form and what the conditions are:
So, as we know that Barium is the metal and it belongs to the ‘Group $ - 2 $ of the periodic table. And it forms an ion with the $ 2 $ positive charge i.e. $ + 2 $ : $ B{a^{2 + }} $
On the other hand, ‘Fluorine’ is the non-metal which is present in the ‘group $ - 17 $ ’ of the periodic table and it forms ion easily with the $ - 1 $ negative charge. So, it will be having an anion as $ {F^{ - 1}} $ .
So, to form a compound, both the elements must satisfy the charges of each other and balance the compound.
So as we know from above, Barium bears charge $ + 2 $ and fluorine has a charge of $ - 1 $ . So two atoms of Fluorine are required to satisfy the $ + 2 $ positive charge of Barium.
Hence the compound formed by Ba and F will be $ Ba{F_2} $ i.e. Barium Fluoride.
Note :
Since we know that the bonds formed by the combination of the metal and the non-metal are the ionic bonds. And ionic bonds or ionic compounds are neutral in nature, so they act and the anion needs to balance the charge of each other to form ionic compounds.
Complete Step By Step Answer:
So, let’s first know about the elements, of which symbols are given in the question.
So, ‘Ba’ is basically the element ‘Barium’.
And the symbol ‘F’ stands for the element Fluorine.
So, let’s know in detail about the compound they will form and what the conditions are:
So, as we know that Barium is the metal and it belongs to the ‘Group $ - 2 $ of the periodic table. And it forms an ion with the $ 2 $ positive charge i.e. $ + 2 $ : $ B{a^{2 + }} $
On the other hand, ‘Fluorine’ is the non-metal which is present in the ‘group $ - 17 $ ’ of the periodic table and it forms ion easily with the $ - 1 $ negative charge. So, it will be having an anion as $ {F^{ - 1}} $ .
So, to form a compound, both the elements must satisfy the charges of each other and balance the compound.
So as we know from above, Barium bears charge $ + 2 $ and fluorine has a charge of $ - 1 $ . So two atoms of Fluorine are required to satisfy the $ + 2 $ positive charge of Barium.
Hence the compound formed by Ba and F will be $ Ba{F_2} $ i.e. Barium Fluoride.
Note :
Since we know that the bonds formed by the combination of the metal and the non-metal are the ionic bonds. And ionic bonds or ionic compounds are neutral in nature, so they act and the anion needs to balance the charge of each other to form ionic compounds.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

