
Formula mass unit of ${ Na }_{ 2 }{ CO }_{ 3 }.{ 10H }_{ 2 }{ O }$ is;
a.) ${ 290 }$
b.) ${ 286 }$
c.) ${ 180.02 }$
d.) ${ 105.97 }$
Answer
593.7k+ views
Hint: The formula unit mass is equal to the sum of atomic masses of all the atoms in an empirical formula of the compound. The formula unit mass depends on the molar mass of the substance.
Complete step-by-step answer:
Formula unit mass of ${ Na }_{ 2 }{ CO }_{ 3 }$
Atomic mass of Na = ${ 22.989 }$u
Atomic mass of C = ${ 12.01 }$u
Atomic mass of O = ${ 15.99 }$u
= ${ 2\times atomic\quad mass\quad of\quad Na+1\times atomic\quad mass\quad of\quad C+3\times atomic\quad mass\quad of\quad O }$
Now, put the values of atomic masses, we get
= ${ 2\times 22.989+1\times 12.01+3\times 15.99 }$
= ${ 105.97 }$u
Formula unit mass of ${ 10H }_{ 2 }{ O }$
Atomic mass of H = ${ 1.007 }$u
Atomic mass of O = ${ 15.99 }$u
= ${ 10\times atomic\quad mass\quad of\quad { H }_{ 2 } }{ O }$
Now, put the values of atomic masses, we get
= ${ 10\times 18.02u }$
= ${ 180.02u }$
Hence, the formula unit mass of ${ Na }_{ 2 }{ CO }_{ 3 }.{ 10H }_{ 2 }{ O }$;
= ${ 105.97+180.02 }$u
= ${ 285.99u }$
Additional Information:
The molecular mass of a molecule is the average mass calculated by adding together the atomic weights of the atoms in the molecular formula. Molecular mass is the sum of the atomic masses of the atoms in a molecule.
The formula mass of formula weight of a molecule is the sum of atomic weights of the atoms in its empirical formula. It is the molecular mass of the total compound containing X number of molecules of that compound.
Note: The possibility to make a mistake is that you may confuse between molecular mass and formula mass.
The formula mass and molecular mass are two different terms and should not be confused as implying the same meaning.
Complete step-by-step answer:
Formula unit mass of ${ Na }_{ 2 }{ CO }_{ 3 }$
Atomic mass of Na = ${ 22.989 }$u
Atomic mass of C = ${ 12.01 }$u
Atomic mass of O = ${ 15.99 }$u
= ${ 2\times atomic\quad mass\quad of\quad Na+1\times atomic\quad mass\quad of\quad C+3\times atomic\quad mass\quad of\quad O }$
Now, put the values of atomic masses, we get
= ${ 2\times 22.989+1\times 12.01+3\times 15.99 }$
= ${ 105.97 }$u
Formula unit mass of ${ 10H }_{ 2 }{ O }$
Atomic mass of H = ${ 1.007 }$u
Atomic mass of O = ${ 15.99 }$u
= ${ 10\times atomic\quad mass\quad of\quad { H }_{ 2 } }{ O }$
Now, put the values of atomic masses, we get
= ${ 10\times 18.02u }$
= ${ 180.02u }$
Hence, the formula unit mass of ${ Na }_{ 2 }{ CO }_{ 3 }.{ 10H }_{ 2 }{ O }$;
= ${ 105.97+180.02 }$u
= ${ 285.99u }$
Additional Information:
The molecular mass of a molecule is the average mass calculated by adding together the atomic weights of the atoms in the molecular formula. Molecular mass is the sum of the atomic masses of the atoms in a molecule.
The formula mass of formula weight of a molecule is the sum of atomic weights of the atoms in its empirical formula. It is the molecular mass of the total compound containing X number of molecules of that compound.
Note: The possibility to make a mistake is that you may confuse between molecular mass and formula mass.
The formula mass and molecular mass are two different terms and should not be confused as implying the same meaning.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

