
For decomposition of \[{\mathbf{N}}{{\mathbf{H}}_{\mathbf{3}}}\left( {\mathbf{g}} \right)\] in a sealed tube:
A. ${K_P}$ does not change with pressure
B. Concentration of ${H_2}$ (g) is less than of Nitrogen
C. Concentration of ammonia does not change with pressure
D. None of the above
Answer
571.5k+ views
Hint: In the given question the reaction of decomposition occurs in a sealed tube. So, we have to discuss the reaction of ammonia, in the essence of pressure and concentration of hydrogen and nitrogen gas, by using the following method at constant pressure.
Complete step by step solution:
The Kjeldahl method or we can say Kjeldahl digestion is defined in analytical chemistry as it is a method for the quantitative determination of nitrogen contained in any of the organic substances along with the nitrogen contained in the inorganic compounds such as ammonia.
According to the given question:
A constant temperature is the equilibrium constant that is denoted by \[{K_p}\] for the decomposition reaction is expressed by \[{K_p}\].\[{K_{P}} = \dfrac{{\left( {4{x^2}p} \right)}}{{\left( {1 - {x^2}} \right)}}\] , where $p$ = pressure and $x$ = extent of decomposition and \[{K_p}\] remains constant with change in values of $p$ and $x$.The value of the equilibrium constant is self-regulating and independent of the partial pressure or from degree of dissociation.
The \[{K_p}\] is a constant for a specific reaction at a particular temperature. Therefore, it will not change along with pressure so we can say that the \[{K_p}\] only changes, if temperature is changed.
Hence, option A is correct.
Note: The Kjeldahl method was developed by Johan Kjeldahl, that’s why it is named after him. In this method heating of a sample at a temperature of \[360-410^\circ C\] along with concentrated sulfuric acid which will further decomposes or in other words digests the organic sample by the oxidation reaction which liberate the reduced nitrogen in form of ammonium sulfate.
Complete step by step solution:
The Kjeldahl method or we can say Kjeldahl digestion is defined in analytical chemistry as it is a method for the quantitative determination of nitrogen contained in any of the organic substances along with the nitrogen contained in the inorganic compounds such as ammonia.
According to the given question:
A constant temperature is the equilibrium constant that is denoted by \[{K_p}\] for the decomposition reaction is expressed by \[{K_p}\].\[{K_{P}} = \dfrac{{\left( {4{x^2}p} \right)}}{{\left( {1 - {x^2}} \right)}}\] , where $p$ = pressure and $x$ = extent of decomposition and \[{K_p}\] remains constant with change in values of $p$ and $x$.The value of the equilibrium constant is self-regulating and independent of the partial pressure or from degree of dissociation.
The \[{K_p}\] is a constant for a specific reaction at a particular temperature. Therefore, it will not change along with pressure so we can say that the \[{K_p}\] only changes, if temperature is changed.
Hence, option A is correct.
Note: The Kjeldahl method was developed by Johan Kjeldahl, that’s why it is named after him. In this method heating of a sample at a temperature of \[360-410^\circ C\] along with concentrated sulfuric acid which will further decomposes or in other words digests the organic sample by the oxidation reaction which liberate the reduced nitrogen in form of ammonium sulfate.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

