
For AB bond if percent ionic character is plotted against electronegativity difference . The shape of the curve would look like:
A.A
B.B
C.C
D.D

Answer
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Hint: We know that Electronegativity is a degree of an attraction of atoms for electrons in a bond. Electronegativity tells us the number of electrons a particular atom has. We know that the electronegativity of an atom starts from the value ranging from 0 to 4; the greater the value, the atom would be more electronegative, and the more attractive would be attraction of the electrons present in a chemical bond.
Complete answer:
We need to remember that if the electronegativity difference between the two atoms is less than units the type of bond is nonpolar.
We can say if the electronegativity difference between the two atoms is units then the type of bond is polar covalent.
If the electronegativity difference between two atoms is greater than units then the type of bond is ionic.
We can give the percentage of ionic character by the equation,
Percentage of ionic character=
So, from the above relationship, we can observe that when gets increased, the percentage of ionic character would also increase. Fifty percent of ionic character takes place when the difference in electronegativity between the atoms is equal to 1.7. This is exhibited from curve C and so this is the most appropriate.
Therefore, the option (C) is correct.
If the value of electronegativity is equal to 1.7, the ionic character would be fifty percent and covalent character would be fifty percent.
If the value of electronegativity is greater than 1.7, the ionic character would be more than fifty percent and covalent character would be less than fifty percent.
If the value of electronegativity is lesser than 1.7, the ionic character would be less than fifty percent and covalent character would be greater than fifty percent.
Note:
We have to know that polarity of the bond and ionic character increases with difference in electronegativity. We can calculate the percent ionic character by calculating charge on each atom and the ionic character percent is found from the ratio of the original charge to the charge present on a single electron.
Complete answer:
We need to remember that if the electronegativity difference between the two atoms is less than
We can say if the electronegativity difference between the two atoms is
If the electronegativity difference between two atoms is greater than
We can give the percentage of ionic character by the equation,
Percentage of ionic character=
So, from the above relationship, we can observe that when
Therefore, the option (C) is correct.
If the value of electronegativity is equal to 1.7, the ionic character would be fifty percent and covalent character would be fifty percent.
If the value of electronegativity is greater than 1.7, the ionic character would be more than fifty percent and covalent character would be less than fifty percent.
If the value of electronegativity is lesser than 1.7, the ionic character would be less than fifty percent and covalent character would be greater than fifty percent.
Note:
We have to know that polarity of the bond and ionic character increases with difference in electronegativity. We can calculate the percent ionic character by calculating charge on each atom and the ionic character percent is found from the ratio of the original charge to the charge present on a single electron.
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