
For AB bond if percent ionic character is plotted against electronegativity difference . The shape of the curve would look like:
A.A
B.B
C.C
D.D

Answer
484.8k+ views
Hint: We know that Electronegativity is a degree of an attraction of atoms for electrons in a bond. Electronegativity tells us the number of electrons a particular atom has. We know that the electronegativity of an atom starts from the value ranging from 0 to 4; the greater the value, the atom would be more electronegative, and the more attractive would be attraction of the electrons present in a chemical bond.
Complete answer:
We need to remember that if the electronegativity difference between the two atoms is less than units the type of bond is nonpolar.
We can say if the electronegativity difference between the two atoms is units then the type of bond is polar covalent.
If the electronegativity difference between two atoms is greater than units then the type of bond is ionic.
We can give the percentage of ionic character by the equation,
Percentage of ionic character=
So, from the above relationship, we can observe that when gets increased, the percentage of ionic character would also increase. Fifty percent of ionic character takes place when the difference in electronegativity between the atoms is equal to 1.7. This is exhibited from curve C and so this is the most appropriate.
Therefore, the option (C) is correct.
If the value of electronegativity is equal to 1.7, the ionic character would be fifty percent and covalent character would be fifty percent.
If the value of electronegativity is greater than 1.7, the ionic character would be more than fifty percent and covalent character would be less than fifty percent.
If the value of electronegativity is lesser than 1.7, the ionic character would be less than fifty percent and covalent character would be greater than fifty percent.
Note:
We have to know that polarity of the bond and ionic character increases with difference in electronegativity. We can calculate the percent ionic character by calculating charge on each atom and the ionic character percent is found from the ratio of the original charge to the charge present on a single electron.
Complete answer:
We need to remember that if the electronegativity difference between the two atoms is less than
We can say if the electronegativity difference between the two atoms is
If the electronegativity difference between two atoms is greater than
We can give the percentage of ionic character by the equation,
Percentage of ionic character=
So, from the above relationship, we can observe that when
Therefore, the option (C) is correct.
If the value of electronegativity is equal to 1.7, the ionic character would be fifty percent and covalent character would be fifty percent.
If the value of electronegativity is greater than 1.7, the ionic character would be more than fifty percent and covalent character would be less than fifty percent.
If the value of electronegativity is lesser than 1.7, the ionic character would be less than fifty percent and covalent character would be greater than fifty percent.
Note:
We have to know that polarity of the bond and ionic character increases with difference in electronegativity. We can calculate the percent ionic character by calculating charge on each atom and the ionic character percent is found from the ratio of the original charge to the charge present on a single electron.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

Trending doubts
Father of Indian ecology is a Prof R Misra b GS Puri class 12 biology CBSE

Who is considered as the Father of Ecology in India class 12 biology CBSE

Enzymes with heme as prosthetic group are a Catalase class 12 biology CBSE

A deep narrow valley with steep sides formed as a result class 12 biology CBSE

An example of ex situ conservation is a Sacred grove class 12 biology CBSE

Why is insulin not administered orally to a diabetic class 12 biology CBSE
