
How to find the velocity of the car after collision?
Answer
547.8k+ views
Hint: The collision can be elastic or inelastic. Elastic collision obeys both conservations of momentum and kinetic energy but inelastic collision doesn’t obey conservation of kinetic energy. The collision of cars falls under Inelastic collision where kinetic energy is not conserved. Inelastic collision obeys Conservation of Momentum. So we can say that momentum before collision=momentum after the collision.
Complete answer:
The term Momentum refers to a quantity that a moving object possesses. It is defined as the product of mass and velocity and its units are $kgm{s^{ - 1}}$ or \[Ns\] . It is represented by the letter. In the given question collision of the car is an inelastic collision that obeys conservation of momentum.
Momentum $P = m \times v$, where m is the mass of the object and \[v\] is the velocity of the object.
By conservation of momentum,
Momentum before collision = Momentum after collision
Lets us assume ${m_1}$ and ${v_1}$ be the mass and velocity of the car before collision, ${m_2}$ and ${v_2}$ be the mass and velocity of the colliding object before the collision and ${v_f}$ be the final velocity. Then,
$\Rightarrow {m_1} \times {v_1} + {m_2} \times {v_2} = \left( {{m_1} + {m_2}} \right) \times {v_f}$
If the initial mass and velocity of the car and the colliding object are given we can easily find the velocity of the car after collision from the below equation.
\[\Rightarrow {v_f} = \dfrac{{{m_1} \times {v_1} + {m_2} \times {v_2}}}{{{m_1} + {m_2}}}\]
Note: Understand what is elastic collision and inelastic collision. Try to derive the equations using conservation of mass for the inelastic collision. If the collision is elastic, use both conservation of momentum and conservation of kinetic energy, then equate both equations to get the final velocity.
Complete answer:
The term Momentum refers to a quantity that a moving object possesses. It is defined as the product of mass and velocity and its units are $kgm{s^{ - 1}}$ or \[Ns\] . It is represented by the letter. In the given question collision of the car is an inelastic collision that obeys conservation of momentum.
Momentum $P = m \times v$, where m is the mass of the object and \[v\] is the velocity of the object.
By conservation of momentum,
Momentum before collision = Momentum after collision
Lets us assume ${m_1}$ and ${v_1}$ be the mass and velocity of the car before collision, ${m_2}$ and ${v_2}$ be the mass and velocity of the colliding object before the collision and ${v_f}$ be the final velocity. Then,
$\Rightarrow {m_1} \times {v_1} + {m_2} \times {v_2} = \left( {{m_1} + {m_2}} \right) \times {v_f}$
If the initial mass and velocity of the car and the colliding object are given we can easily find the velocity of the car after collision from the below equation.
\[\Rightarrow {v_f} = \dfrac{{{m_1} \times {v_1} + {m_2} \times {v_2}}}{{{m_1} + {m_2}}}\]
Note: Understand what is elastic collision and inelastic collision. Try to derive the equations using conservation of mass for the inelastic collision. If the collision is elastic, use both conservation of momentum and conservation of kinetic energy, then equate both equations to get the final velocity.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

