
Find the value of x so that the inclination of the line joining the points (x, -3) and (2, 5) is \[{{135}^{\circ }}\].
Answer
554.7k+ views
Hint: We know that the slope of a line joining the two points \[\left( {{x}_{1}},{{y}_{1}} \right)\] and \[\left( {{x}_{2}},{{y}_{2}} \right)\] is equal to the tangent of the angle made by the line with x-axis in anticlockwise direction given by as follows:
\[slope=\tan \theta =\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\]
Complete step-by-step solution:
We have been given a line joining the points (x, -3) and (2, 5) which makes an angle of \[{{135}^{\circ }}\] with the x-axis.
We know that the slope of a line joining the two points \[\left( {{x}_{1}},{{y}_{1}} \right)\] and \[\left( {{x}_{2}},{{y}_{2}} \right)\] is equal to the tangent of the angle made by the line with x-axis in anticlockwise direction given by as follows:
\[slope=\tan \theta =\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\]
So we have \[\theta ={{135}^{\circ }},{{x}_{1}}=2,{{x}_{2}}=x,{{y}_{1}}=5,{{y}_{2}}=-3\]
\[\Rightarrow \tan {{135}^{\circ }}=\dfrac{-3-5}{x-2}\]
Since we know that \[\tan {{135}^{\circ }}=\tan \left( {{90}^{\circ }}+{{45}^{\circ }} \right)=-\cot {{45}^{\circ }}=-1\] as in second quadrant tangent function is negative.
\[\begin{align}
& \Rightarrow -1=\dfrac{-3-5}{x-2} \\
& \Rightarrow -1=\dfrac{-8}{x-2} \\
\end{align}\]
On cross multiplication, we get as follows:
\[\Rightarrow -x+2=-8\]
On adding - 2 to both the sides of the equation, we get as follows:
\[\begin{align}
& \Rightarrow -x-2+2=-8-2 \\
& \Rightarrow -x=-10 \\
& \Rightarrow x=10 \\
\end{align}\]
Therefore the value of x is equal to 10.
Note: Use the value of \[\tan {{135}^{\circ }}\] very carefully as sometimes we used the value of \[\tan {{135}^{\circ }}\] as equal to 1 which is which is wrong and thus gives the wrong answer. Also, substitute the values of \[{{x}_{1}},{{x}_{2}},{{y}_{1}},{{y}_{2}}\] carefully in the formula of slope of the line. Also, remember that in \[\tan \theta \], \[\theta \] is the angle between the line and the x-axis in an anticlockwise direction with the x-axis.
\[slope=\tan \theta =\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\]
Complete step-by-step solution:
We have been given a line joining the points (x, -3) and (2, 5) which makes an angle of \[{{135}^{\circ }}\] with the x-axis.
We know that the slope of a line joining the two points \[\left( {{x}_{1}},{{y}_{1}} \right)\] and \[\left( {{x}_{2}},{{y}_{2}} \right)\] is equal to the tangent of the angle made by the line with x-axis in anticlockwise direction given by as follows:
\[slope=\tan \theta =\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\]
So we have \[\theta ={{135}^{\circ }},{{x}_{1}}=2,{{x}_{2}}=x,{{y}_{1}}=5,{{y}_{2}}=-3\]
\[\Rightarrow \tan {{135}^{\circ }}=\dfrac{-3-5}{x-2}\]
Since we know that \[\tan {{135}^{\circ }}=\tan \left( {{90}^{\circ }}+{{45}^{\circ }} \right)=-\cot {{45}^{\circ }}=-1\] as in second quadrant tangent function is negative.
\[\begin{align}
& \Rightarrow -1=\dfrac{-3-5}{x-2} \\
& \Rightarrow -1=\dfrac{-8}{x-2} \\
\end{align}\]
On cross multiplication, we get as follows:
\[\Rightarrow -x+2=-8\]
On adding - 2 to both the sides of the equation, we get as follows:
\[\begin{align}
& \Rightarrow -x-2+2=-8-2 \\
& \Rightarrow -x=-10 \\
& \Rightarrow x=10 \\
\end{align}\]
Therefore the value of x is equal to 10.
Note: Use the value of \[\tan {{135}^{\circ }}\] very carefully as sometimes we used the value of \[\tan {{135}^{\circ }}\] as equal to 1 which is which is wrong and thus gives the wrong answer. Also, substitute the values of \[{{x}_{1}},{{x}_{2}},{{y}_{1}},{{y}_{2}}\] carefully in the formula of slope of the line. Also, remember that in \[\tan \theta \], \[\theta \] is the angle between the line and the x-axis in an anticlockwise direction with the x-axis.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

