Find the value of \[\tan {30^ \circ }\cot {30^ \circ }\].
Answer
588.6k+ views
Hint:
In trigonometry the terms tan and cot stand for tangent and cotangent respectively. We have some formulas in trigonometry which relate these two ratios. One of them is \[\tan \theta = \dfrac{1}{{\cot \theta }}\]. Using this relation the given problem can be evaluated.
Complete step by step solution:
Tan or cot functions stand for tangent and cotangent of an angle respectively in trigonometry. The tangent of an angle is also defined by the ratio of the sin of the angle to the cosine of the angle, while the cotangent is the ratio of the cosine of the angle to the sine of the angle.
Now the cotangent of an angle is the reciprocal of the tangent of the angle.
We have to evaluate \[\tan {30^ \circ }\cot {30^ \circ }\]….(1)
Now we can rewrite \[\tan {30^ \circ } = \dfrac{1}{{\cot {{30}^ \circ }}}\]…(2)
Substituting (2) in (1) we get:
\[\tan {30^ \circ }\cot {30^ \circ }\] \[ = \dfrac{1}{{\cot {{30}^ \circ }}}\cot {30^ \circ }\]
\[ \Rightarrow \] \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = 1\]
Observe that we could also rewrite \[\cot {30^ \circ } = \dfrac{1}{{\tan {{30}^ \circ }}}\] and substitute in equation (1), to get the same result.
Hence, \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = 1\].
Note:
This problem could also be evaluated by using the values of the standard angles. Students must memorise the values of \[{0^ \circ },{30^ \circ },{45^ \circ },{60^ \circ },{90^ \circ }\] of the trigonometric functions \[\sin ,\cos ,\tan ,\cot ,\sec ,\cos ec\].
Now \[\tan {30^ \circ } = \dfrac{1}{{\sqrt 3 }}\]
\[\cot {30^ \circ } = \sqrt 3 \]
\[\therefore \] \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = \dfrac{1}{{\sqrt 3 }}\sqrt 3 \] \[ = 1\].
Note that none of the trigonometric ratios have any unit as they are ratios of similar quantities.
In trigonometry the terms tan and cot stand for tangent and cotangent respectively. We have some formulas in trigonometry which relate these two ratios. One of them is \[\tan \theta = \dfrac{1}{{\cot \theta }}\]. Using this relation the given problem can be evaluated.
Complete step by step solution:
Tan or cot functions stand for tangent and cotangent of an angle respectively in trigonometry. The tangent of an angle is also defined by the ratio of the sin of the angle to the cosine of the angle, while the cotangent is the ratio of the cosine of the angle to the sine of the angle.
Now the cotangent of an angle is the reciprocal of the tangent of the angle.
We have to evaluate \[\tan {30^ \circ }\cot {30^ \circ }\]….(1)
Now we can rewrite \[\tan {30^ \circ } = \dfrac{1}{{\cot {{30}^ \circ }}}\]…(2)
Substituting (2) in (1) we get:
\[\tan {30^ \circ }\cot {30^ \circ }\] \[ = \dfrac{1}{{\cot {{30}^ \circ }}}\cot {30^ \circ }\]
\[ \Rightarrow \] \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = 1\]
Observe that we could also rewrite \[\cot {30^ \circ } = \dfrac{1}{{\tan {{30}^ \circ }}}\] and substitute in equation (1), to get the same result.
Hence, \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = 1\].
Note:
This problem could also be evaluated by using the values of the standard angles. Students must memorise the values of \[{0^ \circ },{30^ \circ },{45^ \circ },{60^ \circ },{90^ \circ }\] of the trigonometric functions \[\sin ,\cos ,\tan ,\cot ,\sec ,\cos ec\].
Now \[\tan {30^ \circ } = \dfrac{1}{{\sqrt 3 }}\]
\[\cot {30^ \circ } = \sqrt 3 \]
\[\therefore \] \[\tan {30^ \circ }\cot {30^ \circ }\] \[ = \dfrac{1}{{\sqrt 3 }}\sqrt 3 \] \[ = 1\].
Note that none of the trigonometric ratios have any unit as they are ratios of similar quantities.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

What is the full form of POSCO class 10 social science CBSE

What planets have no moons Which one has only one moon class 10 physics CBSE

Define Potential, Developed, Stock and Reserved resources

In cricket, which Indian bowler is known as the "Yorker King"?

The diagonals of a rhombus are 10cm and 24cm Find the class 10 maths CBSE

