How do you find the value of \[\cot 45^\circ \]?
Answer
580.8k+ views
Hint:
In the given question, we have been asked the exact value of a trigonometric ratio with a constant angle. By exact value, it means that if the value is in fractions, we have to convert it to decimals. This is achieved by dividing the numerator by the denominator. If the denominator is an irrational number, then we shift the irrational number to the numerator by rationalizing it.
Complete step by step answer:
We know, \[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\]
So, we write the values of sine and cosine for those values and then divide them.
Now as we know, \[\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}\]
And we also know that, \[\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}\]
Hence we get, \[\cot 45^\circ = \dfrac{{\cos 45^\circ }}{{\sin 45^\circ }} = \dfrac{{\dfrac{1}{{\sqrt 2 }}}}{{\dfrac{1}{{\sqrt 2 }}}} = 1\]
Hence, the value of \[\cot 45^\circ \] is \[1\].
Note:
So, for solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we write the formula which connects the two things. We have to take care if the denominator is irrational, if it is then we have to rationalize. When we are rationalizing the denominator as it is the only place where we could make an error.
In the given question, we have been asked the exact value of a trigonometric ratio with a constant angle. By exact value, it means that if the value is in fractions, we have to convert it to decimals. This is achieved by dividing the numerator by the denominator. If the denominator is an irrational number, then we shift the irrational number to the numerator by rationalizing it.
Complete step by step answer:
We know, \[\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}\]
So, we write the values of sine and cosine for those values and then divide them.
Now as we know, \[\cos 45^\circ = \dfrac{1}{{\sqrt 2 }}\]
And we also know that, \[\sin 45^\circ = \dfrac{1}{{\sqrt 2 }}\]
Hence we get, \[\cot 45^\circ = \dfrac{{\cos 45^\circ }}{{\sin 45^\circ }} = \dfrac{{\dfrac{1}{{\sqrt 2 }}}}{{\dfrac{1}{{\sqrt 2 }}}} = 1\]
Hence, the value of \[\cot 45^\circ \] is \[1\].
Note:
So, for solving questions of such type, we first write what has been given to us. Then we write down what we have to find. Then we write the formula which connects the two things. We have to take care if the denominator is irrational, if it is then we have to rationalize. When we are rationalizing the denominator as it is the only place where we could make an error.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, what is the term for a bowler taking five wickets in an innings?

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

What is deficiency disease class 10 biology CBSE

