Find the value of: \[8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1\]
Answer
600.9k+ views
Hint:
Here, we will find the value of the given arithmetic expression. We will use the BODMAS rule and properties of Integers to find the value of the given arithmetic expression. An arithmetic expression is defined as an expression with the numbers and arithmetic operators like plus, minus, etc.
Complete step by step solution:
We are given with an arithmetic expression \[8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1\].
Now, we will use the BODMAS rule and the Properties of Integers to find the value of the given arithmetic expression.
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 - 2 + 3 + 1\]
First adding the terms from the right, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 - 2 + 4\]
Subtracting the terms from the right, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 + 2\]
Now, again by using the BODMAS rule, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 4\]
Now, by subtracting the numbers in the expression, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 4\]
Therefore, the value of the given arithmetic expression \[8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1\] is \[4\].
Additional information:
The properties of integers are that the product of two positive integers is always a positive integer, the product of two negative integers is always a positive integer and the product of a positive integer and a negative integer is always a negative integer.
Note:
We know that BODMAS rule states that the first operation has to be done which is in the brackets, next the operation applies on the indices or order, then it moves on to the division and multiplication and then using addition and subtraction we will simplify the expression. If addition or subtraction and division or multiplication are in the same calculations, then it has to be done from left to right.
Here, we will find the value of the given arithmetic expression. We will use the BODMAS rule and properties of Integers to find the value of the given arithmetic expression. An arithmetic expression is defined as an expression with the numbers and arithmetic operators like plus, minus, etc.
Complete step by step solution:
We are given with an arithmetic expression \[8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1\].
Now, we will use the BODMAS rule and the Properties of Integers to find the value of the given arithmetic expression.
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 - 2 + 3 + 1\]
First adding the terms from the right, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 - 2 + 4\]
Subtracting the terms from the right, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 6 + 2\]
Now, again by using the BODMAS rule, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 8 - 4\]
Now, by subtracting the numbers in the expression, we get
\[ \Rightarrow 8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1 = 4\]
Therefore, the value of the given arithmetic expression \[8 - 6 + \left( { - 2} \right) - \left( { - 3} \right) + 1\] is \[4\].
Additional information:
The properties of integers are that the product of two positive integers is always a positive integer, the product of two negative integers is always a positive integer and the product of a positive integer and a negative integer is always a negative integer.
Note:
We know that BODMAS rule states that the first operation has to be done which is in the brackets, next the operation applies on the indices or order, then it moves on to the division and multiplication and then using addition and subtraction we will simplify the expression. If addition or subtraction and division or multiplication are in the same calculations, then it has to be done from left to right.
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