
Find the sum of all odd numbers between 100 and 200.
Answer
601.2k+ views
Hint: Here we will use the arithmetic progression concepts to find the sum of all odd numbers between 100 and 200.
Complete step-by-step answer:
You have to find out the sum of all odd numbers between 100 and 200.
In terms of series it is written as $101 + 103 + 105 + ............. + 199$.
So you know this form an A.P with first term$({a_1}) = 101$and last term$({a_l}) = 199$with common difference$(d) = 103 - 101 = 2$.
First find out the number of terms,
\[
\Rightarrow ({a_l}) = ({a_1}) + (n - 1)d \\
\Rightarrow 199 = 101 + (n - 1)2 \\
\Rightarrow \dfrac{{199 - 101}}{2} + 1 = n \\
\Rightarrow n = 50 \\
\]
Sum of the given series is ${S_n} = \dfrac{n}{2}({a_1} + {a_l})$
$ \Rightarrow {S_n} = \dfrac{{50}}{2}(199 + 101) = 25(200) = 5000$
So this your required sum.
Note: In this type of question always remember the formulas of Arithmetic Progression (A.P), it will help you find your desired answer.
Complete step-by-step answer:
You have to find out the sum of all odd numbers between 100 and 200.
In terms of series it is written as $101 + 103 + 105 + ............. + 199$.
So you know this form an A.P with first term$({a_1}) = 101$and last term$({a_l}) = 199$with common difference$(d) = 103 - 101 = 2$.
First find out the number of terms,
\[
\Rightarrow ({a_l}) = ({a_1}) + (n - 1)d \\
\Rightarrow 199 = 101 + (n - 1)2 \\
\Rightarrow \dfrac{{199 - 101}}{2} + 1 = n \\
\Rightarrow n = 50 \\
\]
Sum of the given series is ${S_n} = \dfrac{n}{2}({a_1} + {a_l})$
$ \Rightarrow {S_n} = \dfrac{{50}}{2}(199 + 101) = 25(200) = 5000$
So this your required sum.
Note: In this type of question always remember the formulas of Arithmetic Progression (A.P), it will help you find your desired answer.
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