Question

How do you find the solution set for \[\dfrac{2}{3}a-\dfrac{1}{5}a=2\]?

Answer 1

Hint: This is a linear equation in one variable as there is only one variable in an equation. In the given question, the variable is the letter ‘a’, to solve this question we need to get ‘a’ on one side of the “equals” sign, and all the other numbers on the other side. To solve this equation for a given variable ‘a’, we have to undo the mathematical operations such as addition, subtraction, multiplication and division that have been done to the variables.

Complete step by step answer:
We have the given equation;
\[\dfrac{2}{3}a-\dfrac{1}{5}a=2\]
Simplifying the LHS of the above linear equation by taking LCM, we get
\[\dfrac{10}{15}a-\dfrac{3}{15}a=2\]
Combining the like terms of the above equation, we get
\[\dfrac{7}{15}a=2\]
Multiply both the side of the above equation by 15, we get
\[7a=30\]
Now solving for the value of ‘a’.
Divide both the sides of the equation by 7, we get
\[a=\dfrac{30}{7}\]

Therefore,
The possible value of \[a\ is\ \dfrac{30}{7}\].

Additional information:
In the given question, no mathematical formula is being used; only the mathematical operations such as addition, subtraction, multiplication and division is used.
Use addition or subtraction properties of equality to gather variable terms on one side of the equation and constant on the other side of the equation.
Use the multiplication or division properties of equality to form the coefficient of the variable term equivalent to 1.

Note: The important thing to recollect about any equation is that the ‘equals’ sign represents a balance. What the sign says is that what’s on the left-hand side is strictly an equal to what’s on the right-hand side. It is the type of question where only mathematical operations such as addition, subtraction, multiplication and division is used.