Find the solution of \[x - \dfrac{1}{8} = \dfrac{3}{4}\].
Answer
570.9k+ views
Hint: Linear equations are the equations in which the variables are raised to the power equal to one. The linear equations are classified into different types based on the number of variables in the equation.
Complete step-by-step solution:
According to the question, to solve the given equation we should first evaluate it and give it a form of equation.
In order to isolate “x”, we should add \[18\] to both sides of the equation. This will keep the equation balanced and undo the \[ - 18\] already on the left hand side. This gives:
\[
x - \dfrac{1}{8} + \dfrac{1}{8} = \dfrac{3}{4} + \dfrac{1}{8} \\
\Rightarrow x = \dfrac{3}{4} + \dfrac{1}{8} \\
\]
In order to add fractions, we must have a common denominator. We can achieve this by multiplying \[\dfrac{3}{4}\] by \[\dfrac{2}{2}\], which is equal to\[1\]. This will change how the fraction looks but won't change its actual value.
\[
x = \dfrac{3}{4}\left( {\dfrac{2}{2}} \right) + \dfrac{1}{8} \\
\Rightarrow x = \dfrac{6}{8} + \dfrac{1}{8} \\
\]
Now that the fractions have equal denominators, we can add the numerators and keep the denominators the same.
\[
x = \dfrac{{6 + 1}}{8} \\
\Rightarrow x = \dfrac{7}{8} \\
\]
Hence, the solution is\[\dfrac{7}{8}\].
Note: Linear equations in one variable are the equation which consists of one variable. Linear equations in two variables are variables which have two variables. Standard method of linear equation eases the method of solving the equation. The linear equation in one variable is written in the form of\[ax + b = 0\]. The linear equation in two variables is written in the form of\[ax + by + c = 0\]. The linear equation in three variables is written in the form of\[ax + by + cz + d = 0\].
Complete step-by-step solution:
According to the question, to solve the given equation we should first evaluate it and give it a form of equation.
In order to isolate “x”, we should add \[18\] to both sides of the equation. This will keep the equation balanced and undo the \[ - 18\] already on the left hand side. This gives:
\[
x - \dfrac{1}{8} + \dfrac{1}{8} = \dfrac{3}{4} + \dfrac{1}{8} \\
\Rightarrow x = \dfrac{3}{4} + \dfrac{1}{8} \\
\]
In order to add fractions, we must have a common denominator. We can achieve this by multiplying \[\dfrac{3}{4}\] by \[\dfrac{2}{2}\], which is equal to\[1\]. This will change how the fraction looks but won't change its actual value.
\[
x = \dfrac{3}{4}\left( {\dfrac{2}{2}} \right) + \dfrac{1}{8} \\
\Rightarrow x = \dfrac{6}{8} + \dfrac{1}{8} \\
\]
Now that the fractions have equal denominators, we can add the numerators and keep the denominators the same.
\[
x = \dfrac{{6 + 1}}{8} \\
\Rightarrow x = \dfrac{7}{8} \\
\]
Hence, the solution is\[\dfrac{7}{8}\].
Note: Linear equations in one variable are the equation which consists of one variable. Linear equations in two variables are variables which have two variables. Standard method of linear equation eases the method of solving the equation. The linear equation in one variable is written in the form of\[ax + b = 0\]. The linear equation in two variables is written in the form of\[ax + by + c = 0\]. The linear equation in three variables is written in the form of\[ax + by + cz + d = 0\].
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

