Answer

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**Hint:**If the degree of an equation is one, then it is a linear equation. The graph of a linear equation is a straight line. The standard form of the equation of the straight line is \[ax+by+c=0\]. We can find the slope intercepts of the line using the coefficients of the equation of the straight line. The slope of the straight line is \[\dfrac{-a}{b}\], we can find the slope by substituting the values of coefficients of the straight line equation.

**Complete step by step solution:**

We are given an equation of the straight line \[x-4y=8\], we need to find the slope of this line. Subtracting 8from both sides of the above equation, it can be expressed as, \[x-4y-8=0\]. We know that the standard form of the equation of the straight line is \[ax+by+c=0\]. The slope of the straight line is \[\dfrac{-a}{b}\]. Comparing the given equation with the standard form of straight line, we get \[a=1,b=-4\And c=-8\].

Thus, we can find the slope of the given straight line as \[slope=\dfrac{-a}{b}\]. Substituting the values, we get

\[\Rightarrow slope=\dfrac{-1}{-4}=\dfrac{1}{4}\]

Thus, the slope of the straight line is \[\dfrac{1}{4}\].

We can also plot the graph of the straight line using the given equation as,

**Note:**We can also use the slope-intercept form of the equation of straight line to find the slope, the slope-intercept form is \[y=mx+c\], here m is the slope of the line, and c is its Y-intercept. To convert it to this form, we need to take y to one side of the equation and make its coefficient equals to one.

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