How do you find the slope of line \[x = 1\]?
Answer
603.6k+ views
Hint: In the given question, we have been given an equation in two variables. We have to plot the line on a graph that forms from this equation. To do that, we first convert the given equation to slope-intercept form. From there, we find out the value of slope and the y-intercept. We plot a point at the y-intercept on the y-axis. From there, we move up or down and then right or left depending upon the coefficient of \[x\] and \[y\] respectively and join the points to form the line.
Formula Used:
The standard form of a linear equation in slope-intercept form is:
\[y = mx + b\]
Complete step by step answer:
The given equation is \[x = 1\].
We first convert this equation to the slope-intercept form,
\[y = mx + b\]
\[\left( 0 \right)y = \left( 1 \right)x - 1\]
Hence, the slope of the line, \[m = 1\].
Now, clearly, this equation is an equation of a vertical line. In this vertical line, for each value of \[y\], the corresponding value of \[x\] is \[1\].
Since \[x\] is never going to be zero, there is no y-intercept.
But we have x-intercept, \[\left( {0,1} \right)\].
Hence, we can graph it out like this:
Note:
In this question, we only need to know one thing – how to get the points for the graph and then, how to plot the points on the graph. Then we just calculate the values from the equation, plot them on the graph, join the points on the graph and we get the line that marks the required equation.
Formula Used:
The standard form of a linear equation in slope-intercept form is:
\[y = mx + b\]
Complete step by step answer:
The given equation is \[x = 1\].
We first convert this equation to the slope-intercept form,
\[y = mx + b\]
\[\left( 0 \right)y = \left( 1 \right)x - 1\]
Hence, the slope of the line, \[m = 1\].
Now, clearly, this equation is an equation of a vertical line. In this vertical line, for each value of \[y\], the corresponding value of \[x\] is \[1\].
Since \[x\] is never going to be zero, there is no y-intercept.
But we have x-intercept, \[\left( {0,1} \right)\].
Hence, we can graph it out like this:
Note:
In this question, we only need to know one thing – how to get the points for the graph and then, how to plot the points on the graph. Then we just calculate the values from the equation, plot them on the graph, join the points on the graph and we get the line that marks the required equation.
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

