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Find the relative molecular mass of methyl alcohol (CH3OH) , if 160gm of the alcohol on vaporization has a volume of 112 litres at STP.
(A) 16gm
(B) 32gm
(C) 160gm
(D) 80gm

Answer
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Hint: Here, we use the concept of moles to calculate the amount of water formed. It can be calculated by dividing the mass of a substance present in a mixture by its molar mass:
The number of moles of a substance =Mass of the substance in the mixtureMolar mass of the substance
Another important concept coming into use is that one mole of a gaseous substance occupies 22.4litresvolume.

Complete answer:
The questions requires us to calculate the relative molar mass of methyl alcohol under given conditions, where mass (w) and volume of the alcohol vaporized is 160gm and 112litres(at STP) respectively.
We know that one mole of a gaseous substance occupies 22.4litresvolume. Using this relation, we can calculate the number of moles occupied by 112litres.
Number of moles occupied by 112litres of gas  = 11222.4=5moles(1)
Since we know the mass of methyl alcohol vaporized, we can substitute it in the following equation relating number of moles:
The number of moles of a substance =Mass of the substance in the mixtureMolar mass of the substance
=wM
=160M(2)
In (2), we can substitute with (1) in the LHS. On rearranging the equation so as to calculate relative molar mass (M)of methyl alcohol, we get:
M=1605
=32gm
Hence, the relative molecular mass of methyl alcohol (CH3OH) , if 160gm of the alcohol on vaporization has a volume of 112 litres at STP is (B) 32gm .

Note:
There exists an equation relating vapour density and molar mass, where:
Molarmass=2×Vapourdensity
This equation comes into play if we are provided with the vapour density of the substance and are supposed to find its molar mass, or vice versa.
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