
Find the number of diagonals of a hexagon.
Answer
602.7k+ views
Hint- In order to solve this question, we will use formula for number of diagonals of a polygon i.e. $\dfrac{{n\left( {n - 3} \right)}}{2}$ .In this way we will get our desired diagonals.
Complete Step-by-Step solution:
Now, we know that in a hexagon there are 6 vertices and we will find the number of diagonals by using the formula given below.
$ \Rightarrow \dfrac{{n\left( {n - 3} \right)}}{2}$
Where, $n = $ number of vertices of hexagon
Now , $n = 6,$
Putting the value of n=6 in the above formula, we will find the number of diagonals of the hexagon.
Therefore, number of diagonal of hexagon$ = \dfrac{{6\left( {6 - 3} \right)}}{2}$
Or $ = \dfrac{{6 \times 3}}{2}$
Or $ = \dfrac{{18}}{2}$
Or $ = 9$
Hence, there are $9$ diagonals of a hexagon.
Note-Whenever we face these type of questions the key concept is that we have to count the vertices of the polygon and put that count as $n$ in the formula like we did in this question here we simply count the number of vertices of hexagon and then we put that count as $n$ in the formula and thus we get our desired answer.
Complete Step-by-Step solution:
Now, we know that in a hexagon there are 6 vertices and we will find the number of diagonals by using the formula given below.
$ \Rightarrow \dfrac{{n\left( {n - 3} \right)}}{2}$
Where, $n = $ number of vertices of hexagon
Now , $n = 6,$
Putting the value of n=6 in the above formula, we will find the number of diagonals of the hexagon.
Therefore, number of diagonal of hexagon$ = \dfrac{{6\left( {6 - 3} \right)}}{2}$
Or $ = \dfrac{{6 \times 3}}{2}$
Or $ = \dfrac{{18}}{2}$
Or $ = 9$
Hence, there are $9$ diagonals of a hexagon.
Note-Whenever we face these type of questions the key concept is that we have to count the vertices of the polygon and put that count as $n$ in the formula like we did in this question here we simply count the number of vertices of hexagon and then we put that count as $n$ in the formula and thus we get our desired answer.
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