Answer
Verified
420.3k+ views
Hint: We will convert equation \[2x+5y+6=0\] into slope intercept form \[y=mx+c\] and then get the slope from it. Then we will substitute this slope and the coordinate (2,4) in point slope form \[y-{{y}_{1}}=m(x-{{x}_{1}})\] to get our answer.
Complete step-by-step answer:
Before proceeding with the question, we should know the concepts related to the equation of lines and its different forms.
Linear equations are a combination of constants and variables.
The most common form of linear equations is slope-intercept form, which is represented as;
\[y=mx+c.....(1)\] where y and x are the points in the x-y plane, m is the slope of the line (also called gradient) and c is the intercept (a constant value).
For example, \[y=5x+2\]. In this slope(m) is 5 and intercept is 2.
In point slope form of linear equation, a straight line equation is formed by considering the points in x-y plane, such that:
\[y-{{y}_{1}}=m(x-{{x}_{1}}).......(2)\] where \[({{x}_{1}},{{y}_{1}})\] are the coordinates of the line.
Now transforming \[2x+5y+6=0\] in slope intercept form to find the slope of the equation. We get,
\[y=-\dfrac{2}{5}x-\dfrac{6}{5}.....(3)\]
Now on comparing equation (3) with equation (1) we get the slope of this line \[m=-\dfrac{2}{5}\].
Now it is mentioned in the question that the equation of the line we have to find is parallel to \[2x+5y+6=0\] and hence the slopes of both these equations will be equal. So now substituting the value of m in equation (2) we get,
\[y-{{y}_{1}}=-\dfrac{2}{5}(x-{{x}_{1}}).......(4)\]
And it is also mentioned in the question that the line passes through (2, 4). So now substituting \[{{x}_{1}}=2\] and \[{{y}_{1}}=4\] in equation (4) we get,
\[y-4=-\dfrac{2}{5}(x-2).......(5)\]
Now rearranging and simplifying equation (5) we get,
\[\begin{align}
& \,\Rightarrow 5y-20=-2x+4 \\
& \Rightarrow 2x+5y-24=0 \\
\end{align}\]
Hence the line parallel to \[2x+5y+6=0\] and passing through (2, 4) is \[2x+5y-24=0\].
Note: An alternate and less time consuming solution is
The equation of line is \[2x+5y+6=0......(6)\] So equation of any line parallel to given line can be written as \[2x+5y+k=0.......(7)\]
The line passes through (2,4) so substituting these coordinates in equation (7) we get,
\[\begin{align}
& \,\Rightarrow 2\times 2+5\times 4+k=0 \\
& \,\Rightarrow k=-4-20=-24 \\
\end{align}\]
So the line parallel to \[2x+5y+6=0\] is \[2x+5y-24=0\].
Complete step-by-step answer:
Before proceeding with the question, we should know the concepts related to the equation of lines and its different forms.
Linear equations are a combination of constants and variables.
The most common form of linear equations is slope-intercept form, which is represented as;
\[y=mx+c.....(1)\] where y and x are the points in the x-y plane, m is the slope of the line (also called gradient) and c is the intercept (a constant value).
For example, \[y=5x+2\]. In this slope(m) is 5 and intercept is 2.
In point slope form of linear equation, a straight line equation is formed by considering the points in x-y plane, such that:
\[y-{{y}_{1}}=m(x-{{x}_{1}}).......(2)\] where \[({{x}_{1}},{{y}_{1}})\] are the coordinates of the line.
Now transforming \[2x+5y+6=0\] in slope intercept form to find the slope of the equation. We get,
\[y=-\dfrac{2}{5}x-\dfrac{6}{5}.....(3)\]
Now on comparing equation (3) with equation (1) we get the slope of this line \[m=-\dfrac{2}{5}\].
Now it is mentioned in the question that the equation of the line we have to find is parallel to \[2x+5y+6=0\] and hence the slopes of both these equations will be equal. So now substituting the value of m in equation (2) we get,
\[y-{{y}_{1}}=-\dfrac{2}{5}(x-{{x}_{1}}).......(4)\]
And it is also mentioned in the question that the line passes through (2, 4). So now substituting \[{{x}_{1}}=2\] and \[{{y}_{1}}=4\] in equation (4) we get,
\[y-4=-\dfrac{2}{5}(x-2).......(5)\]
Now rearranging and simplifying equation (5) we get,
\[\begin{align}
& \,\Rightarrow 5y-20=-2x+4 \\
& \Rightarrow 2x+5y-24=0 \\
\end{align}\]
Hence the line parallel to \[2x+5y+6=0\] and passing through (2, 4) is \[2x+5y-24=0\].
Note: An alternate and less time consuming solution is
The equation of line is \[2x+5y+6=0......(6)\] So equation of any line parallel to given line can be written as \[2x+5y+k=0.......(7)\]
The line passes through (2,4) so substituting these coordinates in equation (7) we get,
\[\begin{align}
& \,\Rightarrow 2\times 2+5\times 4+k=0 \\
& \,\Rightarrow k=-4-20=-24 \\
\end{align}\]
So the line parallel to \[2x+5y+6=0\] is \[2x+5y-24=0\].
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Write an application to the principal requesting five class 10 english CBSE
Difference Between Plant Cell and Animal Cell
a Tabulate the differences in the characteristics of class 12 chemistry CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
Discuss what these phrases mean to you A a yellow wood class 9 english CBSE
List some examples of Rabi and Kharif crops class 8 biology CBSE