
Find the differential coefficient of $\sqrt {\tan \sqrt x } $ .
Answer
575.4k+ views
Hint: Differential coefficient of a function is another term for the derivative of that function. So, we will differentiate the given function step by step and then we will proceed towards the final solution.
Complete step-by-step answer:
Let the given function be denoted by $y = \sqrt {\tan \sqrt x } $
Now, we will differentiate the given equation with respect to x. The differentiation will be done step by step. On differentiating the equation with respect to x, we get,
$\dfrac{{dy}}{{dx}} = \dfrac{{d(\sqrt {\tan \sqrt x } )}}{{dx}}$
=$\dfrac{1}{{2\sqrt {\tan \sqrt x } }}{\sec ^2}\sqrt x \dfrac{1}{{2\sqrt x }}$
In the above differentiation, we have used the differentiation of the functions as $\left( {\dfrac{{d\left( {\sqrt y } \right)}}{{dx}} = \dfrac{1}{{2\sqrt y }}} \right)$, and $\left( {\dfrac{{d\left( {\tan x} \right)}}{{dx}} = {{\sec }^2}x} \right)$.
Here, we have first differentiated the function$\sqrt {\tan \sqrt x } $after that we have differentiated the function $\tan \sqrt x $and lastly differentiated \[\sqrt x \].
Simplifying the above equation, we get
$\dfrac{{dy}}{{dx}} = \dfrac{{{{\sec }^2}\sqrt x }}{{4\sqrt {x\tan \sqrt x } }}$
Therefore, the differential coefficient of $\sqrt {\tan \sqrt x } $will be $\dfrac{{{{\sec }^2}x}}{{4\sqrt {x\tan \sqrt x } }}$.
Additional Information: Differential basically refers to the infinitesimal differences or generally to the functions’ derivative.
A derivative is the change in a function while a differential coefficient is the change between two variables. Hence, we can say that the derivative is always a ratio of the differentials.
A coefficient is usually a constant quantity but the differential coefficient of any function is a constant function only and only if the given function is a linear function.
Note: In such questions where we are required to find the differential coefficient, we generally differentiate the given function as many times as the order of differential coefficient. For e.g., if nth differential coefficient is required, then we just differentiate the function n times.
Complete step-by-step answer:
Let the given function be denoted by $y = \sqrt {\tan \sqrt x } $
Now, we will differentiate the given equation with respect to x. The differentiation will be done step by step. On differentiating the equation with respect to x, we get,
$\dfrac{{dy}}{{dx}} = \dfrac{{d(\sqrt {\tan \sqrt x } )}}{{dx}}$
=$\dfrac{1}{{2\sqrt {\tan \sqrt x } }}{\sec ^2}\sqrt x \dfrac{1}{{2\sqrt x }}$
In the above differentiation, we have used the differentiation of the functions as $\left( {\dfrac{{d\left( {\sqrt y } \right)}}{{dx}} = \dfrac{1}{{2\sqrt y }}} \right)$, and $\left( {\dfrac{{d\left( {\tan x} \right)}}{{dx}} = {{\sec }^2}x} \right)$.
Here, we have first differentiated the function$\sqrt {\tan \sqrt x } $after that we have differentiated the function $\tan \sqrt x $and lastly differentiated \[\sqrt x \].
Simplifying the above equation, we get
$\dfrac{{dy}}{{dx}} = \dfrac{{{{\sec }^2}\sqrt x }}{{4\sqrt {x\tan \sqrt x } }}$
Therefore, the differential coefficient of $\sqrt {\tan \sqrt x } $will be $\dfrac{{{{\sec }^2}x}}{{4\sqrt {x\tan \sqrt x } }}$.
Additional Information: Differential basically refers to the infinitesimal differences or generally to the functions’ derivative.
A derivative is the change in a function while a differential coefficient is the change between two variables. Hence, we can say that the derivative is always a ratio of the differentials.
A coefficient is usually a constant quantity but the differential coefficient of any function is a constant function only and only if the given function is a linear function.
Note: In such questions where we are required to find the differential coefficient, we generally differentiate the given function as many times as the order of differential coefficient. For e.g., if nth differential coefficient is required, then we just differentiate the function n times.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

