Find the differential coefficient of $\sin {x^3}$.
Answer
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Hint: Here we will find the differential coefficient using the formulae of differentiations and chain rule.
Complete step-by-step answer:
You have to differentiate $\sin {x^3}$w.r.t x
$ \Rightarrow \dfrac{d}{{dx}}\sin {x^3}$
As you know sin differentiation is cos then re-differentiate ${x^3}$
$ \Rightarrow \cos {x^3}\dfrac{d}{{dx}}{x^3}$
As you know${x^n}$differentiation is $n.{x^{n - 1}}$
$ \Rightarrow \cos {x^3}(3{x^2}) = 3{x^2}\cos {x^3}$
So this is the required answer.
Note: In this type of question always remember the basic differentiation formula. Here students make common mistakes by keeping the answer as $cos {x^3}$ and they do not differentiate ${x^3}$ term. So we have to take care while solving these types of problems.
Complete step-by-step answer:
You have to differentiate $\sin {x^3}$w.r.t x
$ \Rightarrow \dfrac{d}{{dx}}\sin {x^3}$
As you know sin differentiation is cos then re-differentiate ${x^3}$
$ \Rightarrow \cos {x^3}\dfrac{d}{{dx}}{x^3}$
As you know${x^n}$differentiation is $n.{x^{n - 1}}$
$ \Rightarrow \cos {x^3}(3{x^2}) = 3{x^2}\cos {x^3}$
So this is the required answer.
Note: In this type of question always remember the basic differentiation formula. Here students make common mistakes by keeping the answer as $cos {x^3}$ and they do not differentiate ${x^3}$ term. So we have to take care while solving these types of problems.
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