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How do you find the derivative of s=tsint?

Answer
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Hint: Consider ‘s’ in the L.H.S as a function of t and differentiate both the sides with respect to the variable t. Consider ‘s’ as the product of an algebraic function and a trigonometric function. Now, apply the product rule of differentiation given as: - d(u×v)dt=udvdt+vdudt. Here, consider, u = t and v=sint. Use the formula: - dsintdt=cost to simplify the derivative and get the answer.

Complete step by step solution:
Here, we have been provided with the function s=tsint and we are asked to differentiate it. Here we are going to use the product rule of differentiation to get the answer.
s=tsint
Clearly, we can see that we have ‘s’ as a function of t. Now, we can assume the given function as the product of an algebraic function (t) and a trigonometric function (sint). So, we have,
s=t×sint
Let us assume t as ‘u’ and sint as ‘v’. So, we have,
s=u×v
Differentiating both the sides with respect to t, we get,
dsdt=d(u×v)dt
Now, applying the product rule of differentiation given as: - d(u×v)dt=udvdt+vdudt, we get,
dsdt=[udvdt+vdudt]
Substituting the assumed values of u and v, we get,
dsdt=[tdsintdt+tdtdt]
We know that dsintdt=cost, so we have,
dsdt=[tcost+sint×1]dsdt=(tcost+sint)
Hence, the above relation is our answer.

Note: One may note that whenever we are asked to differentiate a product of two or more functions we apply the product rule. You must remember all the basic rules and formulas of differentiation like: - the product rule, chain rule, uv rule etc. as they are frequently used in both differential and integral calculus. Remember the derivatives of some common functions like: algebraic functions, trigonometric functions, logarithmic functions, exponential functions etc. as we may be asked to find the derivative of the product of any two of these listed functions.