Question

Find the density of the cork
$\left( A \right)0.24{\text{ kgc}}{{\text{m}}^{{\text{ - 3}}}}$
$\left( B \right)0.24{\text{ g}}{{\text{m}}^{{\text{ - 3}}}}$
$\left( C \right)0.24{\text{ kg}}{{\text{m}}^{{\text{ - 3}}}}$
$\left( D \right)0.24{\text{ gc}}{{\text{m}}^{{\text{ - 3}}}}$

Answer 1

- Hint: In this question use the standard mass of cork as 1.2 grams and volume as 5.0 $c{m^3}$. Then the direct formula for density that is $\rho = \dfrac{M}{V}$ . This will help get the right answer.

Complete step-by-step solution -

As we know, the density $\left( \rho \right)$ of any material is the ratio of mass (M) of material in grams to the volume (V) of material in cubic centimeters.
So the density of cork is
$ \Rightarrow \rho = \dfrac{M}{V}$ gm/$c{m^3}$
Now as we know that the mass (M) of the cork is 1.2 grams and volume (V) of the cork is 5.0 $cm^3$.
So the density of the cork is
$ \Rightarrow \rho = \dfrac{{1.2}}{5} = 0.24$ gm/$c{m^3}$.
So the density of cork is 0.24 gm/$c{m^3}$(or) 0.24 ${\text{ gc}}{{\text{m}}^{{\text{ - 3}}}}$

Hence option (D) is correct.

Note – The units are what we need to take care of while solving problems of such kind. Density is defined as the degree of compactness of a substance. It is advised to remember the standard values of mass and volume of cork, sometimes it’s provided in the question paper. Cork is an impermeable buoyant material and is widely used.