
Find the coordinates of points of trisection of the line segment joining the points P (-3, 4) and Q (4, 5).
Answer
598.5k+ views
Hint: To solve this problem we need to have knowledge on trisection concept, section formula and basic calculation. Generally trisection means dividing the line segment in the ratio 1:2 or 2:1 internally.
Complete step-by-step answer:
Here we have to find the coordinates of point of trisection of a line segment that joining the given two points P and Q
We know that trisection divides the line segment in the ratio 1:2 or 2:1 internally.
Let the line segment be PQ.
Let A (x, y) divides the line segment PQ in the ratio 1:2.
As we know that the section formula is
$x = \dfrac{{m{x_2} + n{x_1}}}{{m + n}}$ ,$y = \dfrac{{m{y_2} + n{y_1}}}{{m + n}}$
Now by using the section formula let us find the A (x, y) coordinates, where the ratio m: n=1:2 and point are P (-3, 4) and Q (4, 5).
$x = \dfrac{{1 \times 4 + 2 \times - 3}}{{1 + 2}} = \dfrac{{ - 2}}{3}\left( {{x_1} = - 3,{x_2} = 4} \right)$
$y = \dfrac{{1 \times 5 + 2 \times 4}}{{1 + 2}} = \dfrac{{13}}{3}\left( {{y_1} = 4,{y_2} = 5} \right)$
So the coordinates of A is $\left( {\dfrac{{ - 2}}{3},\dfrac{{13}}{3}} \right)$.
Similarly, let us find the coordinates of B (x, y) which divides the lines segment PQ in the ratio of 2:1
Now again by using the section formula let us find the B (x, y) coordinates, where the ratio m: n= 2: 1and point are P (-3, 4) and Q (4, 5).
$x = \dfrac{{2 \times 4 + 1 \times - 3}}{{2 + 1}} = \dfrac{5}{3}\left( {{x_1} = - 3,{x_2} = 4} \right)$
${y_2} = \dfrac{{2 \times 5 + 1 \times 4}}{{2 + 1}} = \dfrac{{14}}{3}\left( {{y_1} = 4,{y_2} = 5} \right)$
So the coordinates of B is $\left( {\dfrac{5}{3},\dfrac{{14}}{3}} \right)$.
Hence the point of trisection are $\left( {\dfrac{5}{3},\dfrac{{14}}{3}} \right)$ and $\left( {\dfrac{{ - 2}}{3},\dfrac{{13}}{3}} \right)$
Note: Generally we get confused with trisection and section formula. Section formula locates the points on dividing the line segment in desired ratio, which means generally it helps us to find the coordinate points. And trisection means dividing the line segment into three equal parts or dividing the line segment in the ratio 1:2 or 2:1 internally.
Complete step-by-step answer:
Here we have to find the coordinates of point of trisection of a line segment that joining the given two points P and Q
We know that trisection divides the line segment in the ratio 1:2 or 2:1 internally.
Let the line segment be PQ.
Let A (x, y) divides the line segment PQ in the ratio 1:2.
As we know that the section formula is
$x = \dfrac{{m{x_2} + n{x_1}}}{{m + n}}$ ,$y = \dfrac{{m{y_2} + n{y_1}}}{{m + n}}$
Now by using the section formula let us find the A (x, y) coordinates, where the ratio m: n=1:2 and point are P (-3, 4) and Q (4, 5).
$x = \dfrac{{1 \times 4 + 2 \times - 3}}{{1 + 2}} = \dfrac{{ - 2}}{3}\left( {{x_1} = - 3,{x_2} = 4} \right)$
$y = \dfrac{{1 \times 5 + 2 \times 4}}{{1 + 2}} = \dfrac{{13}}{3}\left( {{y_1} = 4,{y_2} = 5} \right)$
So the coordinates of A is $\left( {\dfrac{{ - 2}}{3},\dfrac{{13}}{3}} \right)$.
Similarly, let us find the coordinates of B (x, y) which divides the lines segment PQ in the ratio of 2:1
Now again by using the section formula let us find the B (x, y) coordinates, where the ratio m: n= 2: 1and point are P (-3, 4) and Q (4, 5).
$x = \dfrac{{2 \times 4 + 1 \times - 3}}{{2 + 1}} = \dfrac{5}{3}\left( {{x_1} = - 3,{x_2} = 4} \right)$
${y_2} = \dfrac{{2 \times 5 + 1 \times 4}}{{2 + 1}} = \dfrac{{14}}{3}\left( {{y_1} = 4,{y_2} = 5} \right)$
So the coordinates of B is $\left( {\dfrac{5}{3},\dfrac{{14}}{3}} \right)$.
Hence the point of trisection are $\left( {\dfrac{5}{3},\dfrac{{14}}{3}} \right)$ and $\left( {\dfrac{{ - 2}}{3},\dfrac{{13}}{3}} \right)$
Note: Generally we get confused with trisection and section formula. Section formula locates the points on dividing the line segment in desired ratio, which means generally it helps us to find the coordinate points. And trisection means dividing the line segment into three equal parts or dividing the line segment in the ratio 1:2 or 2:1 internally.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

