Question

Find the area of trapezium whose parallel sides 9cm and 5cm respectively and the distance between these sides is 8cm.

Answer 1

Hint: We will put the values of parallel sides and height in the formula area of trapezium. Thereafter we will simplify the values to get the answer. By using the formula: Area of trapezium $ = \dfrac{1}{2}$(sum of two parallel sides)$ \times \,h$.


Complete step by step solution:
 Here,

ABCD is a trapezium in figure and parallel side are shown and $h = 8cm.$ the length of parallel sides are $9cm and 5cm$
As we know that the formula of area of a trapezium,
Area of trapezium $ = \dfrac{1}{2}$(sum of two parallel sides)$ \times \,h$.
Now, we will substitute the value of parallel sides and height, we have
Area of trapezium $ = \dfrac{1}{2}\left( {9 + 5} \right) \times 8$
Area of trapezium $ = \dfrac{1}{2} \times 14 \times 8$
Area of trapezium$ = 14 \times 4$
Area of trapezium $ = 56\,c{m^2}$
Hence area of trapezium is $56\,c{m^2}$.
Additional information: A trapezium is a quadrilateral with at least one pair of parallel sides.
The perimeter of trapezium $ = $sum of length of sides of trapezium.


Note: Remember square quantity is used in the area of any figure must put the exact value in the formula to get the correct answer.