
Find the area of the triangular field whose sides are \[91m,{\text{ }}98m{\text{ }}and{\text{ }}105m\]. Find the height corresponding to
the longest side.
Answer
507.9k+ views
Hint: Using Heron’s formula to find area of the triangle as three sides are known and then using basic area
formula to find height corresponding to the longest side.
Formula: $S = \dfrac{{a + b + c}}{2},\,\,\,Area = \sqrt {S\left( {S - a} \right)\left( {S - b} \right)\left( {S - c} \right)} $
Complete step by step solution:
1. As three sides of the triangle are known to us. Therefore, we use Heron’s formula to find the area of the triangle.
Here $a = 91,\,\,b = 98\,\,and\,\,c = 105$
2. Calculating \[S\](semi perimeter) by using,
$S = \dfrac{{a + b + c}}{2}$,
Substituting the values of a, b and c in the above formula,
$S = \dfrac{{91 + 98 + 105}}{2}$
$S = \dfrac{{294}}{2}$
$S = 147$
3. Heron’s Formula is given as
$Area\,of\,triangle = \sqrt {S(S - a)(S - b)(S - c)} $,
Substituting the values of \[S,{\text{ }}a,{\text{ }}b\]and\[c\].
$Area{\text{ }}of{\text{ }}triangle = \sqrt {147\left( {147 - 91} \right)\left( {147 - 98} \right)\left( {147 - 105} \right)} $
$Area{\text{ }}of{\text{ }}triangle = \sqrt {147 \times 56 \times 49 \times 42} $,
Making prime factors of numbers,
$Area{\text{ }}of{\text{ }}triangle = \sqrt {3 \times 7 \times 7 \times 7 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 \times 3 \times 2} $
$Area{\text{ }}of{\text{ }}trian\lg e = 7 \times 7 \times 7 \times 3 \times 2 \times 2$
$Area{\text{ }}of{\text{ }}triangle = 4116$
4. Therefore, the area of the triangle of given sides is $4116{m^2}$.
5. Also, we know that area of any triangle is given as $\dfrac{1}{2} \times base \times height$
6. To calculate height corresponding to the longest side. We take $105m$ as the base.
Therefore, $Area{\text{ }}of{\text{ }}triangle = \dfrac{1}{2} \times base \times height$
$Height = \dfrac{{2 \times Area{\text{ }}of{\text{ }}triangle}}{{base}}$
Taking area$ = 4116{m^2}$, base $ = 105m$ we have
$Height = \dfrac{{2 \times 4116}}{{105}}$
$Height = 78.4$
7. Hence, height to the corresponding longest side of the triangle is 78.4m.
Note:When length of three sides of a triangle are given,make sure to apply Heron's formula and do not apply the formula of the area of the triangle directly.
formula to find height corresponding to the longest side.
Formula: $S = \dfrac{{a + b + c}}{2},\,\,\,Area = \sqrt {S\left( {S - a} \right)\left( {S - b} \right)\left( {S - c} \right)} $
Complete step by step solution:

1. As three sides of the triangle are known to us. Therefore, we use Heron’s formula to find the area of the triangle.
Here $a = 91,\,\,b = 98\,\,and\,\,c = 105$
2. Calculating \[S\](semi perimeter) by using,
$S = \dfrac{{a + b + c}}{2}$,
Substituting the values of a, b and c in the above formula,
$S = \dfrac{{91 + 98 + 105}}{2}$
$S = \dfrac{{294}}{2}$
$S = 147$
3. Heron’s Formula is given as
$Area\,of\,triangle = \sqrt {S(S - a)(S - b)(S - c)} $,
Substituting the values of \[S,{\text{ }}a,{\text{ }}b\]and\[c\].
$Area{\text{ }}of{\text{ }}triangle = \sqrt {147\left( {147 - 91} \right)\left( {147 - 98} \right)\left( {147 - 105} \right)} $
$Area{\text{ }}of{\text{ }}triangle = \sqrt {147 \times 56 \times 49 \times 42} $,
Making prime factors of numbers,
$Area{\text{ }}of{\text{ }}triangle = \sqrt {3 \times 7 \times 7 \times 7 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 \times 3 \times 2} $
$Area{\text{ }}of{\text{ }}trian\lg e = 7 \times 7 \times 7 \times 3 \times 2 \times 2$
$Area{\text{ }}of{\text{ }}triangle = 4116$
4. Therefore, the area of the triangle of given sides is $4116{m^2}$.
5. Also, we know that area of any triangle is given as $\dfrac{1}{2} \times base \times height$
6. To calculate height corresponding to the longest side. We take $105m$ as the base.
Therefore, $Area{\text{ }}of{\text{ }}triangle = \dfrac{1}{2} \times base \times height$
$Height = \dfrac{{2 \times Area{\text{ }}of{\text{ }}triangle}}{{base}}$
Taking area$ = 4116{m^2}$, base $ = 105m$ we have
$Height = \dfrac{{2 \times 4116}}{{105}}$
$Height = 78.4$
7. Hence, height to the corresponding longest side of the triangle is 78.4m.
Note:When length of three sides of a triangle are given,make sure to apply Heron's formula and do not apply the formula of the area of the triangle directly.
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