Question

Find the additive inverse of the following integers: $6, 9, 123, -76, -85, 1000$

Answer 1

Hint: Here, in this given question, we may use the fact the sum of an integer and the additive inverse of that integer is equal to zero, 0. So, basically if we are given a number then we have to find such a number, which when added to that number gives a sum as 0. An easy way to do that is just to change the sign of the integer to negative if it is positive and to positive if it is negative.

Complete step-by-step answer:
In this given question, we are asked to find the additive inverse of the following integers:
$6, 9, 123, -76, -85, 1000$
Now, we know that the sum of an integer and the additive inverse of that integer is equal to zero, 0.
So, we have to find an integer for each of the given numbers which when added to them respectively, gives a sum as 0.
An easy way to do that is just to change the sign of the integer to negative if it is positive and to positive if it is negative.
So, the additive inverse of $6$ is $-6$ : $6+ (-6) =0$,
The additive inverse of $9$ is $-9$ :   $9+ (-9) =0$,
The additive inverse of $123$ is $-123$ : $123+ (-123) =0$,
The additive inverse of $-76$ is $76$ : $-76+76=0$,
The additive inverse of $-85$ is $85$ : $-85+85=0$,
The additive inverse of $1000$ is $-1000$ : $1000+ (-1000) =0$
Hence, we have found all the additive inverses of the given numbers as the answers to this given question.

Note: While solving such types of questions as given here, we must be very careful not to make any change to the digits of the integers but only to the signs as positive and negative as required.