
Find oxidation number of Sulphur in ${H_2}{S_4}{O_6}$
Answer
546.9k+ views
Hint:In this question, students have to find the oxidation number i.e., oxidation state of sulphur. Oxidation number is defined as the absolute number of electrons that a particle either gains or loses to form a chemical bond with another molecule.
Complete step by step solution:
There are some rules that students need to remember while figuring the oxidation states in a molecule.
-Any Free component has an oxidation number equivalent to zero.
-For monatomic particles the oxidation number consistently has a similar value as the net charge comparing to the particle
-The hydrogen particle has an oxidation condition of $ + 1$. When the bonding takes place with less electronegativity it shows an oxidation number of $ - 1$
-When oxygen is bonded with peroxides, its oxidation state is $ - 2$.
-All group 1 elements and alkali metals have oxidation state $ + 1$.
-Similarly, alkaline earth metals have oxidation state $ + 2$
Now, let us consider oxidation number of sulphur be X
With the help of above rules, we can calculate oxidation number of sulphur as follows:
$2 \times (1) + 4 \times X + 6 \times ( - 2) = 0$
Here 1 is oxidation number of Hydrogen
And -2 is oxidation number of Oxygen
Further solving the above equation we have:
$
2 + 4x - 12 = 0 \\
\Rightarrow 4x = 10 \\
\Rightarrow x = 2.5 \\
$
Hence, from the above explanation we can find that the oxidation number of Sulphur in is ${H_2}{S_4}{O_6}$ 2.5.
Additional Information:${H_2}{S_4}{O_6}$is known as Tetra thionic acid and has unsymmetrical Sulphur atoms. As electronegativity of Oxygen is higher than that of Sulphur, so when the bond will break, Oxygen will have oxidation number -1 and Sulphur will have oxidation number +1.
Note:Students are advised to do all the calculations properly. Also, students should take care of the fact that the electronegativities differ for all the elements in different conditions, so they should abide by the rules thoroughly mentioned above while answering these types of questions. These questions are important for both boards as well as competitive exams.
Complete step by step solution:
There are some rules that students need to remember while figuring the oxidation states in a molecule.
-Any Free component has an oxidation number equivalent to zero.
-For monatomic particles the oxidation number consistently has a similar value as the net charge comparing to the particle
-The hydrogen particle has an oxidation condition of $ + 1$. When the bonding takes place with less electronegativity it shows an oxidation number of $ - 1$
-When oxygen is bonded with peroxides, its oxidation state is $ - 2$.
-All group 1 elements and alkali metals have oxidation state $ + 1$.
-Similarly, alkaline earth metals have oxidation state $ + 2$
Now, let us consider oxidation number of sulphur be X
With the help of above rules, we can calculate oxidation number of sulphur as follows:
$2 \times (1) + 4 \times X + 6 \times ( - 2) = 0$
Here 1 is oxidation number of Hydrogen
And -2 is oxidation number of Oxygen
Further solving the above equation we have:
$
2 + 4x - 12 = 0 \\
\Rightarrow 4x = 10 \\
\Rightarrow x = 2.5 \\
$
Hence, from the above explanation we can find that the oxidation number of Sulphur in is ${H_2}{S_4}{O_6}$ 2.5.
Additional Information:${H_2}{S_4}{O_6}$is known as Tetra thionic acid and has unsymmetrical Sulphur atoms. As electronegativity of Oxygen is higher than that of Sulphur, so when the bond will break, Oxygen will have oxidation number -1 and Sulphur will have oxidation number +1.
Note:Students are advised to do all the calculations properly. Also, students should take care of the fact that the electronegativities differ for all the elements in different conditions, so they should abide by the rules thoroughly mentioned above while answering these types of questions. These questions are important for both boards as well as competitive exams.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

