Question

Find \[\dfrac{6}{13}\div 7\]

Answer 1

Hint: The sum can be done either by using BODMAS(bracket off divide multiply addition subtraction) rule or by doing it by normal convention way.

Complete step-by-step answer:
In BODMAS(bracket off divide multiply addition subtraction) we first need to change \[\dfrac{6}{13}\] Into \[(6\div 13)\] so as to make the equation in acceptable format of BODMAS(bracket off divide multiply addition subtraction).

The steps after changing the format of \[\dfrac{6}{13}\div 7\] is…
\[\begin{gathered}
  & (6\div 13)\div 7 \\
 & \dfrac{(6\div 13)}{7} \\
 & \dfrac{\left( \dfrac{6}{13} \right)}{7}\text{ }\!\![\!\!\text{ bracket has to be done in its own space since it comes first in BODMAS rule }\!\!]\!\!\text{ } \\
 & \dfrac{6}{13\times 7}=\dfrac{6}{91} \\
\end{gathered}\]

We change the \[\dfrac{6}{13}\] To \[(6\div 13)\] because \[13\] is before the external \[\div 7\] so for the \[13\] to not get mixed by \[\div 7\] we put a bracket and proceed the sums through BODMAS.

In a conventional way we do….
\[\begin{gathered}
  & \left( \dfrac{6}{13} \right)\div 7 \\
 & \dfrac{\left( \dfrac{6}{13} \right)}{7}=\dfrac{6}{13\times 7}=\dfrac{6}{91} \\
\end{gathered}\]
We see that the last step was similar to the BODMAS rule one. This is because eventually we need to reach the desired answer one way or the other.

If we want to find the numeric and decimal value of these sums we can do it by using the normal dividend and quotient method.

Note: We have to change the format in BODMAS rule as it is necessary. We need the brackets off(similar to multiply) divide multiply addition subtraction to be seen to us.