
How do you find derivative of $ y = \tan (3x) $
Answer
552.6k+ views
Hint: Here we have to apply the differentiation to y and we differentiate the y with respect to x. The given function can be written as a composite of two functions so we use chain rule to find the derivative. Since it is a trigonometry we have standard differentiation formulas.
Formula used:
The derivative of $ \tan x $ is $ \dfrac{d}{{dx}}(\tan x) = {\sec ^2}x $
The derivative of $ ax $ is $ \dfrac{d}{{dx}}(ax) = a $
Complete step-by-step answer:
In calculus we have two major topics that are differentiation and integration. We can check if the given function is differentiable by using the limit concept. If the limit exists for the given function then it is differentiable.
Now here in this question they have given $ y = \tan (3x) $
We can say that the given function is composite of two functions.
Suppose if we take $ g(x) = 3x $ and $ h(x) = \tan x $ . The composition of function is given as $ g \circ h = h(g(x)) $
Therefore we have
$
g \circ h = h(g(x)) \\
\Rightarrow g \circ h = h(3x) \\
\Rightarrow g \circ h = \tan (3x) \\
\Rightarrow g \circ h = y \;
$
Since the given function is a composite function of two functions then we can use chain rule of derivative to the given function and hence we can find the derivative of the function.
Therefore by applying chain rule of derivative to the function we have
$
\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\tan \left( {3x} \right)} \right) \\
\Rightarrow \dfrac{{dy}}{{dx}} = {\sec ^2}3x \cdot \dfrac{d}{{dx}}\left( {3x} \right) \\
$
Since the derivative of $ \tan x $ is $ {\sec ^2}x $
$ \Rightarrow \dfrac{{dy}}{{dx}} = {\sec ^2}3x \cdot (3) $
Since the derivative of $ ax $ is $ a $
On simplification we have
$ \Rightarrow \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $
Hence we obtained the derivative of $ y = \tan 3x $ is $ \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $
So, the correct answer is “ $ \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $ ”.
Note: The differentiation is the rate of change of a function at a point. We must know about the chain rule of derivatives. The function can be written as a composite of two functions, if the function can be written as a composite of two functions then we can apply the chain rule of derivative. Hence by using the derivative formulas we can solve the function and hence obtain the solution.
Formula used:
The derivative of $ \tan x $ is $ \dfrac{d}{{dx}}(\tan x) = {\sec ^2}x $
The derivative of $ ax $ is $ \dfrac{d}{{dx}}(ax) = a $
Complete step-by-step answer:
In calculus we have two major topics that are differentiation and integration. We can check if the given function is differentiable by using the limit concept. If the limit exists for the given function then it is differentiable.
Now here in this question they have given $ y = \tan (3x) $
We can say that the given function is composite of two functions.
Suppose if we take $ g(x) = 3x $ and $ h(x) = \tan x $ . The composition of function is given as $ g \circ h = h(g(x)) $
Therefore we have
$
g \circ h = h(g(x)) \\
\Rightarrow g \circ h = h(3x) \\
\Rightarrow g \circ h = \tan (3x) \\
\Rightarrow g \circ h = y \;
$
Since the given function is a composite function of two functions then we can use chain rule of derivative to the given function and hence we can find the derivative of the function.
Therefore by applying chain rule of derivative to the function we have
$
\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\tan \left( {3x} \right)} \right) \\
\Rightarrow \dfrac{{dy}}{{dx}} = {\sec ^2}3x \cdot \dfrac{d}{{dx}}\left( {3x} \right) \\
$
Since the derivative of $ \tan x $ is $ {\sec ^2}x $
$ \Rightarrow \dfrac{{dy}}{{dx}} = {\sec ^2}3x \cdot (3) $
Since the derivative of $ ax $ is $ a $
On simplification we have
$ \Rightarrow \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $
Hence we obtained the derivative of $ y = \tan 3x $ is $ \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $
So, the correct answer is “ $ \dfrac{{dy}}{{dx}} = 3{\sec ^2}3x $ ”.
Note: The differentiation is the rate of change of a function at a point. We must know about the chain rule of derivatives. The function can be written as a composite of two functions, if the function can be written as a composite of two functions then we can apply the chain rule of derivative. Hence by using the derivative formulas we can solve the function and hence obtain the solution.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Which prominent US inventor was known as the Wizard class 12 social science CBSE

Which state in India is known as the Granary of India class 12 social science CBSE

Give simple chemical tests to distinguish between the class 12 chemistry CBSE

What is virtual and erect image ?

Explain the energy losses in the transformer How are class 12 physics CBSE

