
Find derivative of $ f(x) = 3x + 2 $ using the first principle of derivative.
Answer
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Hint: The given question wants us to evaluate the derivative of a given linear polynomial function using the first principle of derivative. The first principle of derivative involves the concepts of limits, derivatives, continuity and differentiability. It helps us to determine the derivative of the function using concepts of limits.
Complete step-by-step answer:
Given the function $ f(x) = 3x + 2 $ , we have to calculate the derivative of the function using the first principle of derivatives.
Using formula of first principle of derivatives, we know that derivative of a function is calculated as:
\[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{f(x + h) - f(x)}}{h}\]
So, derivative of the given function $ f(x) = \left( {3x + 2} \right) $ ,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{(3(x + h) + 2) - (3x + 2)}}{h}\]
Simplifying by opening bracket,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{(3x + 3h + 2) - (3x + 2)}}{h}\]
Simplifying further and cancelling the like terms with opposite signs, we get,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{3x + 3h + 2 - 3x - 2}}{h}\]
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{3h}}{h}\]
Cancelling the common factors of numerator and denominator and reducing the fraction in its lowest term, we get
$ = $ \[f'(x) = \mathop {\lim 3}\limits_{h \to 0} \]
On applying limits, we get the derivative of the given function,
$ = $ \[f'(x) = 3\]
Hence, the derivative of $ f(x) = 3x + 2 $ is \[f'(x) = 3\] .
So, the correct answer is “ \[f'(x) = 3\] ”.
Note: There are various methods of finding the derivatives of the given functions. The calculation of derivative using the first principle of derivative is the most basic and core method to find the derivative of a specific function. Another method of finding derivatives of a function can be simply differentiating that particular function with respect to the variable or unknown using some basic differentiation rules like addition rule, subtraction rule, product rule, and quotient rule. This method is comparatively easier as it does not involve concepts limits and continuity.
Complete step-by-step answer:
Given the function $ f(x) = 3x + 2 $ , we have to calculate the derivative of the function using the first principle of derivatives.
Using formula of first principle of derivatives, we know that derivative of a function is calculated as:
\[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{f(x + h) - f(x)}}{h}\]
So, derivative of the given function $ f(x) = \left( {3x + 2} \right) $ ,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{(3(x + h) + 2) - (3x + 2)}}{h}\]
Simplifying by opening bracket,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{(3x + 3h + 2) - (3x + 2)}}{h}\]
Simplifying further and cancelling the like terms with opposite signs, we get,
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{3x + 3h + 2 - 3x - 2}}{h}\]
$ = $ \[f'(x) = \mathop {\lim }\limits_{h \to 0} \dfrac{{3h}}{h}\]
Cancelling the common factors of numerator and denominator and reducing the fraction in its lowest term, we get
$ = $ \[f'(x) = \mathop {\lim 3}\limits_{h \to 0} \]
On applying limits, we get the derivative of the given function,
$ = $ \[f'(x) = 3\]
Hence, the derivative of $ f(x) = 3x + 2 $ is \[f'(x) = 3\] .
So, the correct answer is “ \[f'(x) = 3\] ”.
Note: There are various methods of finding the derivatives of the given functions. The calculation of derivative using the first principle of derivative is the most basic and core method to find the derivative of a specific function. Another method of finding derivatives of a function can be simply differentiating that particular function with respect to the variable or unknown using some basic differentiation rules like addition rule, subtraction rule, product rule, and quotient rule. This method is comparatively easier as it does not involve concepts limits and continuity.
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