
How do you find all the factors of the number $45$ ?
Answer
469.8k+ views
Hint:
For finding the factors we just need to find the factors which will be expressed as a product of two whole numbers. By taking those whole numbers, we will have the factors. So the number which will give the original number which when multiplied all together. And in this way, we can also verify it.
Complete Step by Step Solution:
As we know that the number we have is composite. So now we will find the factor of $45$
So, firstly we will divide the number with the smallest factor,
$ \Rightarrow 45 \times 1 = 45$
Now we will move on to the next number which can be expressed in the form of a product and it will be equal to
$ \Rightarrow 3 \times 15 = 45$
Similarly, we will move on to the next number which can be expressed in the form of a product and it will be equal to
$ \Rightarrow 5 \times 9 = 45$
So, in the end, we had got all the pairs and we cannot move furthermore, as there is no more any pair which can be expressed in the form of product,
So the factors of $45$ will be written as
$ \Rightarrow 1, 3, 5, 9, 15, 45$
Therefore, all the factors of $45$ will be equal to $1, 3, 5, 9, 15$ and $45$.
Note:
From the factors we can see that $3\& 5$ will be the prime numbers. So there is a difference between the factor and the prime factors. As we had already known about the factors, prime factors are those numbers which have exactly two factors and it will be $1$ and itself. It is like writing a number that can be multiplied together to make a new number.
For finding the factors we just need to find the factors which will be expressed as a product of two whole numbers. By taking those whole numbers, we will have the factors. So the number which will give the original number which when multiplied all together. And in this way, we can also verify it.
Complete Step by Step Solution:
As we know that the number we have is composite. So now we will find the factor of $45$
So, firstly we will divide the number with the smallest factor,
$ \Rightarrow 45 \times 1 = 45$
Now we will move on to the next number which can be expressed in the form of a product and it will be equal to
$ \Rightarrow 3 \times 15 = 45$
Similarly, we will move on to the next number which can be expressed in the form of a product and it will be equal to
$ \Rightarrow 5 \times 9 = 45$
So, in the end, we had got all the pairs and we cannot move furthermore, as there is no more any pair which can be expressed in the form of product,
So the factors of $45$ will be written as
$ \Rightarrow 1, 3, 5, 9, 15, 45$
Therefore, all the factors of $45$ will be equal to $1, 3, 5, 9, 15$ and $45$.
Note:
From the factors we can see that $3\& 5$ will be the prime numbers. So there is a difference between the factor and the prime factors. As we had already known about the factors, prime factors are those numbers which have exactly two factors and it will be $1$ and itself. It is like writing a number that can be multiplied together to make a new number.
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