
Find \[{\text{A}}\Delta {\text{B}}\] and by definition: \[{\text{A}} = \left\{ {1,2,3,4,5} \right\}\] and \[{\text{B}} = \left\{ {1,3,5,7} \right\}\].
Answer
564k+ views
Hint: Here, we need to find the value of the expression \[{\text{A}}\Delta {\text{B}}\]. First, we will find the elements that come in set \[{\text{A}}\] but not in set \[{\text{B}}\]. Then, we will find the elements that come in set \[{\text{B}}\] but not in set \[{\text{A}}\]. Finally, we will use the formula for \[{\text{A}}\Delta {\text{B}}\] to find the elements in the set \[{\text{A}}\Delta {\text{B}}\]. The \[\Delta \] represents the symmetric difference of two or more sets. It includes all those elements that come exactly in one set.
Formula Used:
The expression \[{\text{A}}\Delta {\text{B}}\] is given by the union of the elements of the set \[{\text{A}} - {\text{B}}\], and the elements of the set \[{\text{B}} - {\text{A}}\], that is \[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} - {\text{B}}} \right) \cup \left( {{\text{B}} - {\text{A}}} \right)\].
Complete step-by-step answer:
The expression \[{\text{A}}\Delta {\text{B}}\] includes all those elements that come only in set \[{\text{A}}\], or only in set \[{\text{B}}\]. Now, by definition, \[{\text{A}} = \left\{ {1,2,3,4,5} \right\}\] and \[{\text{B}} = \left\{ {1,3,5,7} \right\}\].
The set \[{\text{A}} - {\text{B}}\] includes all those elements that come in set \[{\text{A}}\] but not in set \[{\text{B}}\].
Thus, we get
\[{\text{A}} - {\text{B}} = \left\{ {2,4} \right\}\]
The set \[{\text{B}} - {\text{A}}\] includes all those elements that come in set \[{\text{B}}\] but not in set \[{\text{A}}\].
Thus, we get
\[{\text{B}} - {\text{A}} = \left\{ 7 \right\}\]
The expression \[{\text{A}}\Delta {\text{B}}\] is given by the union of the elements of the set \[{\text{A}} - {\text{B}}\], and the elements of the set \[{\text{B}} - {\text{A}}\].
Therefore, we get
\[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} - {\text{B}}} \right) \cup \left( {{\text{B}} - {\text{A}}} \right)\]
Substituting \[{\text{A}} - {\text{B}} = \left\{ {2,4} \right\}\] and \[{\text{B}} - {\text{A}} = \left\{ 7 \right\}\] in the expression, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4} \right\} \cup \left\{ 7 \right\}\]
The union of two sets is the set of all the elements in the two sets.
Thus, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4,7} \right\}\]
\[\therefore \] We get \[{\text{A}}\Delta {\text{B}}\] as \[\left\{ {2,4,7} \right\}\].
Note: The expression \[{\text{A}}\Delta {\text{B}}\] can be written as the difference in the union and intersection of two sets.
We can also find \[{\text{A}}\Delta {\text{B}}\] using the formula \[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} \cup {\text{B}}} \right) - \left( {{\text{A}} \cap {\text{B}}} \right)\].
Since \[{\text{A}} = \left\{ {1,2,3,4,5} \right\}\] and \[{\text{B}} = \left\{ {1,3,5,7} \right\}\], we can see that
\[\left( {{\text{A}} \cup {\text{B}}} \right) = \left\{ {1,2,3,4,5} \right\} \cup \left\{ {1,3,5,7} \right\} = \left\{ {1,2,3,4,5,7} \right\}\]
The intersection of two sets is said to be the set of those elements which are common in both the sets.
Therefore, we get
\[\left( {{\text{A}} \cap {\text{B}}} \right) = \left\{ {1,2,3,4,5} \right\} \cap \left\{ {1,3,5,7} \right\} = \left\{ {1,3,5} \right\}\]
Now, substituting \[\left( {{\text{A}} \cup {\text{B}}} \right) = \left\{ {1,2,3,4,5,7} \right\}\] and \[\left( {{\text{A}} \cap {\text{B}}} \right) = \left\{ {1,3,5} \right\}\] in the formula , we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {1,2,3,4,5,7} \right\} - \left\{ {1,3,5} \right\}\]
Therefore, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4,7} \right\}\]
\[\therefore \] We get \[{\text{A}}\Delta {\text{B}}\] as \[\left\{ {2,4,7} \right\}\].
Formula Used:
The expression \[{\text{A}}\Delta {\text{B}}\] is given by the union of the elements of the set \[{\text{A}} - {\text{B}}\], and the elements of the set \[{\text{B}} - {\text{A}}\], that is \[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} - {\text{B}}} \right) \cup \left( {{\text{B}} - {\text{A}}} \right)\].
Complete step-by-step answer:
The expression \[{\text{A}}\Delta {\text{B}}\] includes all those elements that come only in set \[{\text{A}}\], or only in set \[{\text{B}}\]. Now, by definition, \[{\text{A}} = \left\{ {1,2,3,4,5} \right\}\] and \[{\text{B}} = \left\{ {1,3,5,7} \right\}\].
The set \[{\text{A}} - {\text{B}}\] includes all those elements that come in set \[{\text{A}}\] but not in set \[{\text{B}}\].
Thus, we get
\[{\text{A}} - {\text{B}} = \left\{ {2,4} \right\}\]
The set \[{\text{B}} - {\text{A}}\] includes all those elements that come in set \[{\text{B}}\] but not in set \[{\text{A}}\].
Thus, we get
\[{\text{B}} - {\text{A}} = \left\{ 7 \right\}\]
The expression \[{\text{A}}\Delta {\text{B}}\] is given by the union of the elements of the set \[{\text{A}} - {\text{B}}\], and the elements of the set \[{\text{B}} - {\text{A}}\].
Therefore, we get
\[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} - {\text{B}}} \right) \cup \left( {{\text{B}} - {\text{A}}} \right)\]
Substituting \[{\text{A}} - {\text{B}} = \left\{ {2,4} \right\}\] and \[{\text{B}} - {\text{A}} = \left\{ 7 \right\}\] in the expression, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4} \right\} \cup \left\{ 7 \right\}\]
The union of two sets is the set of all the elements in the two sets.
Thus, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4,7} \right\}\]
\[\therefore \] We get \[{\text{A}}\Delta {\text{B}}\] as \[\left\{ {2,4,7} \right\}\].
Note: The expression \[{\text{A}}\Delta {\text{B}}\] can be written as the difference in the union and intersection of two sets.
We can also find \[{\text{A}}\Delta {\text{B}}\] using the formula \[{\text{A}}\Delta {\text{B}} = \left( {{\text{A}} \cup {\text{B}}} \right) - \left( {{\text{A}} \cap {\text{B}}} \right)\].
Since \[{\text{A}} = \left\{ {1,2,3,4,5} \right\}\] and \[{\text{B}} = \left\{ {1,3,5,7} \right\}\], we can see that
\[\left( {{\text{A}} \cup {\text{B}}} \right) = \left\{ {1,2,3,4,5} \right\} \cup \left\{ {1,3,5,7} \right\} = \left\{ {1,2,3,4,5,7} \right\}\]
The intersection of two sets is said to be the set of those elements which are common in both the sets.
Therefore, we get
\[\left( {{\text{A}} \cap {\text{B}}} \right) = \left\{ {1,2,3,4,5} \right\} \cap \left\{ {1,3,5,7} \right\} = \left\{ {1,3,5} \right\}\]
Now, substituting \[\left( {{\text{A}} \cup {\text{B}}} \right) = \left\{ {1,2,3,4,5,7} \right\}\] and \[\left( {{\text{A}} \cap {\text{B}}} \right) = \left\{ {1,3,5} \right\}\] in the formula , we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {1,2,3,4,5,7} \right\} - \left\{ {1,3,5} \right\}\]
Therefore, we get
\[ \Rightarrow {\text{A}}\Delta {\text{B}} = \left\{ {2,4,7} \right\}\]
\[\therefore \] We get \[{\text{A}}\Delta {\text{B}}\] as \[\left\{ {2,4,7} \right\}\].
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

