
Find ${a^0} = 1$ is true for all a except
A. -1
B. Negative integers
C. 0
D. 1
Answer
618k+ views
Hint: We know that any non-zero number raised to the power of zero is equal to 1. We need to check out all the options and find the false statement using the information to get to the required answer.
Complete Step-by-Step solution:
Checking all the options we get the only value for $a$ which leaves ${a^0}$ undefined is a = 0.
Putting a = -1 , negative integers and 1 , we get defined value 1 every time. But zero to the power of zero, denoted by ${0^0}$, is a mathematical expression with no agreed-upon value.
Therefore, option (C) is correct.
Note: Some believe that ${0^0}$ should be defined as 1 while others think it is 0, and some believe it is undefined. There are good mathematical arguments for each, and perhaps it is most correctly considered indeterminate. But in mathematics remember that ${0^0}$ is undefined.
Complete Step-by-Step solution:
Checking all the options we get the only value for $a$ which leaves ${a^0}$ undefined is a = 0.
Putting a = -1 , negative integers and 1 , we get defined value 1 every time. But zero to the power of zero, denoted by ${0^0}$, is a mathematical expression with no agreed-upon value.
Therefore, option (C) is correct.
Note: Some believe that ${0^0}$ should be defined as 1 while others think it is 0, and some believe it is undefined. There are good mathematical arguments for each, and perhaps it is most correctly considered indeterminate. But in mathematics remember that ${0^0}$ is undefined.
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