
How would you find a balanced equation of acetylene gas ( ) undergoes combustion to form carbon dioxide and water vapour?
Answer
481.5k+ views
Hint:The combustion of a material is a process where the material or compound reacts with molecular oxygen present in the air in order to form its oxides.
Organic compounds, upon reaction with oxygen, usually form carbon dioxide and water.
The combustion of a material is a process where the material or compound reacts with molecular oxygen present in the air in order to form its oxides.
Organic compounds, upon reaction with oxygen, usually form carbon dioxide and water.
Complete answer:
In order to balance the chemical equation we must first write the skeletal equation taking place in the reaction. As it is well mentioned that the gas is undergoing combustion so we will add oxygen as a reactant along with acetylene. The reaction is as follows,
Now we will consider each of these formulas individually in order to equate the number of atoms on both the sides. At first acetylene, we will write the coefficient one as the number of carbon atoms is higher on the reactant side as it is, and the coefficient of the carbon dioxide as two, to balance the number of carbon atoms on both sides.
As we can see the number of hydrogen atoms is also balanced on both the sides. In case of oxygen atoms, we can see that the number is five on the product side but it is two on the reactant side. So we need to multiply all the coefficients with two except for the oxygen on the reactant side, in order to avoid fractions. We get,
Now we can see that the number of oxygen atoms is five on the product side and two on the reactant side, so we will add a coefficient on the reactant side. We get,
Now, as we can see all the atoms on both the sides are balanced. Hence the equation is balanced.
Note:The balancing of a chemical reaction requires a stepwise analysis of the number of atoms of each element present in the reactant as well as product.
In order to do so, we add required coefficients on either side of the reaction, and check if it is balanced.
Organic compounds, upon reaction with oxygen, usually form carbon dioxide and water.
The combustion of a material is a process where the material or compound reacts with molecular oxygen present in the air in order to form its oxides.
Organic compounds, upon reaction with oxygen, usually form carbon dioxide and water.
Complete answer:
In order to balance the chemical equation we must first write the skeletal equation taking place in the reaction. As it is well mentioned that the gas is undergoing combustion so we will add oxygen as a reactant along with acetylene. The reaction is as follows,
Now we will consider each of these formulas individually in order to equate the number of atoms on both the sides. At first acetylene, we will write the coefficient one as the number of carbon atoms is higher on the reactant side as it is, and the coefficient of the carbon dioxide as two, to balance the number of carbon atoms on both sides.
As we can see the number of hydrogen atoms is also balanced on both the sides. In case of oxygen atoms, we can see that the number is five on the product side but it is two on the reactant side. So we need to multiply all the coefficients with two except for the oxygen on the reactant side, in order to avoid fractions. We get,
Now we can see that the number of oxygen atoms is five on the product side and two on the reactant side, so we will add a coefficient
Now, as we can see all the atoms on both the sides are balanced. Hence the equation is balanced.
Note:The balancing of a chemical reaction requires a stepwise analysis of the number of atoms of each element present in the reactant as well as product.
In order to do so, we add required coefficients on either side of the reaction, and check if it is balanced.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

The flightless birds Rhea Kiwi and Emu respectively class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE
