
Figure shows an elevator cabin, which is moving downwards with constant acceleration a. A particle is projected from corner A, directly towards diagonally opposite corner C, then prove that:
(A) Particle will hit C only when $ a = g $
(B) Particle will hit wall CD if $ a < g $
(C) Particle will hit the roof BC if a>g

Answer
506.4k+ views
Hint
Every object on earth tends to fall towards the ground. So whenever it is thrown upwards with any velocity it always experiences a downward force that is equal to g and makes it follow a projectile path. But when the reference (elevator cabin here) itself is accelerating, both of these quantities add up and give a net direction of acceleration, which the object thrown inside the elevator would also experience.
Complete step by step answer
An accelerating elevator cabin is a non-inertial frame of reference, it is accelerating. This acceleration causes the object to feel a force and to follow a path that is not a straight line, even if it is thrown with a constant velocity and a fixed direction.
We keep the elevator cabin as the frame of reference, as it is non-inertial, and would appear as a pseudo force which acts in the upward direction. We take upwards as positive direction then-
Case (a): When $ a = g $ :
The directions of g and a are opposite, so the relative acceleration of the object is given by:
$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g $
$ {a_{net}} = g - g = 0 $
The object experiences no external force and moves with the constant velocity with which it was projected. It reaches C.
Case (b): When $ a < g $
$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g < 0 $
Therefore the object experiences a net downward force, which causes it to follow a projectile motion, due to which it hits the surface CD.
Case (c): When $ a > g $
$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g > 0 $
Therefore the object experiences a net upwards force, so it follows a projectile motion with upward acceleration, so it hits the roof.
Note
The object is freely falling at all times, or if viewed from an inertial frame of reference, the object only moves with a velocity with which it is projected and follows a projectile path as it would normally do on earth. It is the elevator cabin that accelerates at different rates, which allows the object to either hit C, CD, or the roof. When we take the elevator as a non-inertial frame of reference and assume a pseudo force equal to a in a direction opposite to its original acceleration, the calculation becomes easier.
Every object on earth tends to fall towards the ground. So whenever it is thrown upwards with any velocity it always experiences a downward force that is equal to g and makes it follow a projectile path. But when the reference (elevator cabin here) itself is accelerating, both of these quantities add up and give a net direction of acceleration, which the object thrown inside the elevator would also experience.
Complete step by step answer
An accelerating elevator cabin is a non-inertial frame of reference, it is accelerating. This acceleration causes the object to feel a force and to follow a path that is not a straight line, even if it is thrown with a constant velocity and a fixed direction.
We keep the elevator cabin as the frame of reference, as it is non-inertial, and would appear as a pseudo force which acts in the upward direction. We take upwards as positive direction then-
Case (a): When $ a = g $ :

The directions of g and a are opposite, so the relative acceleration of the object is given by:
$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g $
$ {a_{net}} = g - g = 0 $
The object experiences no external force and moves with the constant velocity with which it was projected. It reaches C.
Case (b): When $ a < g $

$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g < 0 $
Therefore the object experiences a net downward force, which causes it to follow a projectile motion, due to which it hits the surface CD.
Case (c): When $ a > g $

$ {a_{net}} = \vec g + \vec a $
$ {a_{net}} = a - g > 0 $
Therefore the object experiences a net upwards force, so it follows a projectile motion with upward acceleration, so it hits the roof.
Note
The object is freely falling at all times, or if viewed from an inertial frame of reference, the object only moves with a velocity with which it is projected and follows a projectile path as it would normally do on earth. It is the elevator cabin that accelerates at different rates, which allows the object to either hit C, CD, or the roof. When we take the elevator as a non-inertial frame of reference and assume a pseudo force equal to a in a direction opposite to its original acceleration, the calculation becomes easier.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE
