How do you factor completely $16{x^2} - 25{y^2}$?
Answer
574.8k+ views
Hint: We will first of all use the formula ${a^2} - {b^2} = (a - b)(a + b)$ and replace a and b by the required things so that we get the two factors of the given expression.
Complete step-by-step answer:
We are given that we are required to factorize $16{x^2} - 25{y^2}$.
We know that we have an identity given by the following expression:-
$ \Rightarrow {a^2} - {b^2} = (a - b)(a + b)$
Now, replace a by 4x and b by 5y in the above written identity to get the following expression with us:-
$ \Rightarrow {\left( {4x} \right)^2} - {\left( {5y} \right)^2} = (4x - 5y)(4x + 5y)$
Now, if we simplify the squaring on the left hand side, we will then obtain the following expression:-
$ \Rightarrow 16{x^2} - 25{y^2} = (4x - 5y)(4x + 5y)$
Hence, the factors of $16{x^2} - 25{y^2}$ are (4x – 5y) and (4x + 5y).
Note:
The students must note that there is an alternate way to do the same and get the same factors. In that method, we will add and subtract something similar in the given equation so that we can take things common and make the similar factors. This can be done as follows:-
We are given that we are required to factorize $16{x^2} - 25{y^2}$.
Let us add and subtract 20 xy to it. Then, we will obtain the following expression:-
$ \Rightarrow 16{x^2} - 25{y^2} - 20xy + 20xy$
Now, we can re - arrange the terms and write the expression in the above line as the following:-
$ \Rightarrow 16{x^2} - 20xy - 25{y^2} + 20xy$
Now, we will use associative property and combine the terms as pairs in the above given expression to obtain the expression written below:-
$ \Rightarrow \left( {16{x^2} - 20xy} \right) + \left( { - 25{y^2} + 20xy} \right)$
Now, we can take 5x common among the terms $16{x^2}$ and 20 xy given in front and 5y common from $25{y^2}$ and 20 xy given in back, then we will thus obtain the following expression:-
$ \Rightarrow 4x\left( {4x - 5y} \right) + 5y\left( { - 5y + 4x} \right)$
Since we have similar terms in bracket as well, we can take it common to get the following expression:-
$ \Rightarrow (4x - 5y)(4x + 5y)$
Thus we have the required factors.
Complete step-by-step answer:
We are given that we are required to factorize $16{x^2} - 25{y^2}$.
We know that we have an identity given by the following expression:-
$ \Rightarrow {a^2} - {b^2} = (a - b)(a + b)$
Now, replace a by 4x and b by 5y in the above written identity to get the following expression with us:-
$ \Rightarrow {\left( {4x} \right)^2} - {\left( {5y} \right)^2} = (4x - 5y)(4x + 5y)$
Now, if we simplify the squaring on the left hand side, we will then obtain the following expression:-
$ \Rightarrow 16{x^2} - 25{y^2} = (4x - 5y)(4x + 5y)$
Hence, the factors of $16{x^2} - 25{y^2}$ are (4x – 5y) and (4x + 5y).
Note:
The students must note that there is an alternate way to do the same and get the same factors. In that method, we will add and subtract something similar in the given equation so that we can take things common and make the similar factors. This can be done as follows:-
We are given that we are required to factorize $16{x^2} - 25{y^2}$.
Let us add and subtract 20 xy to it. Then, we will obtain the following expression:-
$ \Rightarrow 16{x^2} - 25{y^2} - 20xy + 20xy$
Now, we can re - arrange the terms and write the expression in the above line as the following:-
$ \Rightarrow 16{x^2} - 20xy - 25{y^2} + 20xy$
Now, we will use associative property and combine the terms as pairs in the above given expression to obtain the expression written below:-
$ \Rightarrow \left( {16{x^2} - 20xy} \right) + \left( { - 25{y^2} + 20xy} \right)$
Now, we can take 5x common among the terms $16{x^2}$ and 20 xy given in front and 5y common from $25{y^2}$ and 20 xy given in back, then we will thus obtain the following expression:-
$ \Rightarrow 4x\left( {4x - 5y} \right) + 5y\left( { - 5y + 4x} \right)$
Since we have similar terms in bracket as well, we can take it common to get the following expression:-
$ \Rightarrow (4x - 5y)(4x + 5y)$
Thus we have the required factors.
Recently Updated Pages
Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is the full form of PNG A Petrol Natural Gas B class 10 chemistry CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

In cricket, how many legal balls are there in a standard over?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

