Question

Express 121 as the sum of 11 odd numbers?

Answer 1

Hint: As we all know that Odd numbers are the numbers that cannot be divided by two (2). They are integers and not fractions. An odd number is an integer which takes the form \[{\rm{n}} = 2{\rm{k}} + 1\], where k is an integer. So, we have to start from 1 and go up to the number where their sum will be 121.

Complete step-by-step answer:
As we all know that 121 is the perfect square of 11 i.e. \[121 = {11^2}\]
In mathematics, a perfect square or square number is an integer that is the square of an integer or we can say that it is the product of some integer with itself.
So now starting from 1st number and going up to the number where the total sum of 11 numbers is equal to sum 121
So, we can write 121 as a sum of \[1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21\] which is equal to 121.

Note: We should know the meaning of
Even numbers are any integer that can be divided exactly by 2 is an even number. The last digit is 0, 2, 4, 6 or 8. An even number is an integer which takes the form \[{\rm{n}} = 2{\rm{k}}\], where k is an integer.
Odd numbers are the numbers that cannot be divided by two (2). They are integers and not fractions. An odd number is an integer which takes the form \[{\rm{n}} = 2{\rm{k}} + 1\], where k is an integer.
A perfect square or square number is an integer that is the square of an integer or we can say that it is the product of some integer with itself.
121 can also be written as a sum of \[11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11 + 11\]