Expand using algebraic identity: \[{\left( {b - 7} \right)^2}\]
Answer
624k+ views
Hint: Here, we have to expand the term by using the algebraic identity. Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. In elementary algebra, the symbols representing quantities without having fixed values are known as variables.
Formula used:
We will use the formula of the square of difference of two numbers is given by the algebraic identity \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\] where \[a\] and \[b\] are two numbers.
Complete step-by-step answer:
We are given an algebraic expression \[{\left( {b - 7} \right)^2}\].
Now, we have to expand the algebraic expression using an algebraic identity.
Now, substituting \[a = b\] and \[b = 7\] in the algebraic identity \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\], we have
\[ \Rightarrow {\left( {b - 7} \right)^2} = {b^2} + {7^2} - 2 \cdot b \cdot 7\]
The square of the variable \[b\] is \[{b^2}\] .
The square of the number \[7\] is \[49\] .
The product of the number and the variable is \[14b\] .
So by substituting the values, we have
\[ \Rightarrow {\left( {b - 7} \right)^2} = {b^2} + 49 - 14b\] .
Therefore, the algebraic expansion of \[{\left( {b - 7} \right)^2}\]is \[{b^2} + 49 - 14b\].
Note: The algebraic equations which are valid for all values of variables in them are called algebraic identities. They are also used for the factorization of polynomials. .
An algebraic expression is an expression which consists of variables and constants. In expressions, a variable can take any value. Thus, the expression value can change if the variable values are changed. But algebraic identity is equality which is true for all the values of the variables.
Formula used:
We will use the formula of the square of difference of two numbers is given by the algebraic identity \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\] where \[a\] and \[b\] are two numbers.
Complete step-by-step answer:
We are given an algebraic expression \[{\left( {b - 7} \right)^2}\].
Now, we have to expand the algebraic expression using an algebraic identity.
Now, substituting \[a = b\] and \[b = 7\] in the algebraic identity \[{\left( {a - b} \right)^2} = {a^2} + {b^2} - 2ab\], we have
\[ \Rightarrow {\left( {b - 7} \right)^2} = {b^2} + {7^2} - 2 \cdot b \cdot 7\]
The square of the variable \[b\] is \[{b^2}\] .
The square of the number \[7\] is \[49\] .
The product of the number and the variable is \[14b\] .
So by substituting the values, we have
\[ \Rightarrow {\left( {b - 7} \right)^2} = {b^2} + 49 - 14b\] .
Therefore, the algebraic expansion of \[{\left( {b - 7} \right)^2}\]is \[{b^2} + 49 - 14b\].
Note: The algebraic equations which are valid for all values of variables in them are called algebraic identities. They are also used for the factorization of polynomials. .
An algebraic expression is an expression which consists of variables and constants. In expressions, a variable can take any value. Thus, the expression value can change if the variable values are changed. But algebraic identity is equality which is true for all the values of the variables.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
Guru Purnima speech in English in 100 words class 7 english CBSE

How many crores make 10 million class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

Write a letter to the editor of the national daily class 7 english CBSE

The cost of a pen is Rs 10 and the cost of a pencil class 7 maths CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE


