Question

Example of an aromatic ether is/ are:
A.

B.

C.

D. All of these

Answer 1

Hint: Ether is a functional group having R – O – R arrangement, where R is the alkyl or aryl groups that can be the same or different. Aromatic compounds are the compounds consisting of an alternated double and single bond arrangement that can lead to hyper conjugation, it also follows Huckel rule of aromaticity.

Complete answer:
We have been given various ethers from which we have to find the aromatic ethers. Ethers are a functional group in which oxygen is attached with two alkyl or aryl groups that can be the same or different. Aromaticity of any compound is the property to possess a ring that consists of complete delocalization of pi electrons. The ring should have an alternate conjugate system of single and double bonds to carry on the delocalization of electrons. The compound should be planar along with delocalization of pi electrons.
Among the given ethers, we have all of them containing a ring conjugated system of alternate single and double bonds as follows:

The compound having${{C}_{6}}{{H}_{5}}-O-C{{H}_{2}}-C{{H}_{2}}-CH(C{{H}_{3}})-C{{H}_{3}}$ is also aromatic as it contains a 6 carbon ring with 5 hydrogen atoms making it a planar and aromatic molecule.

Hence, all the given ethers are aromatic. So, option D is correct.

Note:
Apart from being planar and having delocalization, the compound must follow $\left( 4n+2 \right)\pi $ electrons in the ring in order to be aromatic, where n is the integer = 0, 1, 2…etc. These conditions make the compound aromatic. Also the flame test can practically tell if it is aromatic or not. An aromatic compound burns with a smoky flame.